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uysha [10]
3 years ago
11

What is the radius of the circle defined by x^2+2x+y^2+6y-39=0?

Mathematics
1 answer:
MAXImum [283]3 years ago
7 0
Hello : 
<span>x²+2x+y²+6y-39=0
(x²+2x+1)-1 +(y² +6y+9)-9 -39 =0
(x+1)² + (y+3)² = 49 = 7²
</span><span>the radius is : 7</span>
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