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3 years ago

Simplify the following: (4x^-3b^4)^-3

Mathematics

1 answer:

Daniel [21]3 years ago

5 0

$= \frac{1}{(4 {x}^{3} - b^{4} ) {}^{3} }$

Step-by-step explanation:

$(4 {x}^{3} - b ^{4} )^{ - 3}$

<h2>EXPRESS WITH A POSITIVE EXPONENT</h2>

$= \frac{1}{(4 {x}^{3} - b {}^{4} \: )^{3} }$

<h2>there for the equation has a solution</h2>

hope it helps

#carry on learning

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A product is made up of three parts A B and C .The manufacturing in process is such that the probability of A being defective is

Umnica [9.8K]

The probability that there'll be no defective will be 0.504.

<h3>How to calculate the probability?</h3>

Probability of A being defective = 0.2.

Probability of B being defective = 0.1

Probability of C being defective = 0.3.

The probability that there will be no defective will be:

= (1 - 0.2) × (1 - 0.1) × (1 - 0.3)

= 0.8 × 0.9 × 0.7

= 0.504

The probability that there'll be no defect is 0.504.

The probability that there'll be at least two defective part will be:

= (0.2 × 0.1) + (0.2 × 0.3) + (0.1 × 0.3)

= 0.02 + 0.06 + 0.03

= 0.11

The probability that there'll be at least two defects is 0.11.

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2 years ago

How to find 12.5% of 5760

garri49 [273]

The answer of how to find 12.5% of 5760 is 720

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If f(x) = -x + 5 and g(x) = x^2, what is (g° (-1)?

ipn [44]

Answer:

$(g\circ f)(-1)=36$

Step-by-step explanation:

We are given the two functions:

$f(x)=-x+5\text{ and } g(x)=x^2$

And we want to find:

$(g\circ f)(-1)$

This is equivalent to:

$=g(f(-1))$

So, evaluating f(-1) first, we acquire:

$f(-1)=-(-1)+5=6$

Then by substitution:

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So:

$=(6)^2=36$

Therefore:

$(g\circ f)(-1)=36$

Your answer is indeed correct.

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Sixteen is seven plus three time a number. Find the number

Amanda [17]

Answer:

x=3

Step-by-step explanation:

16-7=9

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4 years ago

The gas tank in Sharon’s car can hold up to 16.5 gal of gas. About how many liters of gas can the tank hold? 1 L≈1.06 qt

Andreas93 [3]

we know that

a) $1$ gallon is equal to $4$ quarter of gallon

by proportion

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by proportion

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the answer is the option

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