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Rus_ich [418]
3 years ago
11

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics
2 answers:
Phoenix [80]3 years ago
8 0

Answer:

2x + 3y +1

Step-by-step explanation:

-2x + 4x -6y + 9y +3 -2 (arranging)

2x + 3y + 1

umka2103 [35]3 years ago
3 0

Answer: 2+3+1

Step-by-step explanation:

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Subtract top exponent from bottom. answer is a^2 b^7 c
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3 years ago
Question 15 of 25
Slav-nsk [51]

Answer:

Step-by-step explanation:

Polynomials are factored after they are set equal to 0. This i because the factors of the polynomial are also known as the x-intercepts, and x-intercepts exist where y = 0. Therefore, if the factors of the polynomial are

(x + 8)(x + 4) = 0, then by the Zero Product Property,

x + 8 = 0 so x = -8 or

x + 4 = 0 so x = -4. Choice A.

5 0
3 years ago
The first rule is to add 10, then divide by 2 starting from 2. The second rule is to multiply by 3, then subtract 2 starting fro
julsineya [31]

Answer: (2, 2), (6, 4), (8, 10), (9, 28)

Step-by-step explanation:

The first four ordered pairs using the two sequences are:(2, 2), (6, 4), (8, 10), (9, 28)

The first rule is to add 10, then divide by 2 starting from 2

Add/Divide:

10=2+10=12

2=12÷2=6

Add/divide again:

10=6+10=16

2 = 20÷2 = 10 2=16÷2=8

Add/divide again:

10=8+10=18

2=18÷2=9

5 0
2 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
A random sample of 144 observations produced a sample proportion of 0.4. An approximate 90% confidence interval for the populati
EleoNora [17]

Answer:

CI =(0.333, 0.480)

Step-by-step explanation:

The formula for calculating the confidence interval is expressed as shown;

CI = p±Z * √p(1-p)/n±0.5/n

Z is the z-score at 90% confidence

p is the sample proportion

n is the sample size

Given n = 144, p = 0.4 and z-score at 90%  CI = 1.645 (from z table)

Substituting this values;

CI = p ± 1.645*√0.4(1-0.4)/144 ±0.5/n

CI = 0.4 ± 1.645*√0.4(0.6)/144 ± 0.5/144

CI = 0.4 ±1.645 * √0.24/144 ± 0.00347

CI = 0.4 ±1.645 * 0.04087± 0.00347

CI = 0.4±0.06723±0.00347

CI =(0.333, 0.480)

7 0
3 years ago
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