Help me! l want the correct answers °_°
1 answer:
Answer:
see explanation
Step-by-step explanation:
(a)
The angle on the circumference is half the central angle , that is
∠ A = ∠ BOC ÷ 2 = 50° ÷ 2 = 25°
(b)
Δ AOC is isosceles ( OA = OC , radii of the same circle ) then the base angles are congruent , that is
∠ ACO = ∠ A = 25°
(c)
Δ BOC is isosceles ( OB = OC, radii of the same circle ) then the base angles are congruent, that is
∠ BCO = =
= 65°
(d)
∠ ACO + ∠ BCO = 25° + 65° = 90° ( angle in a semicircle )
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Answer:
=
Step-by-step explanation:
AS we can see in the figure that a beam or a rod is balanced by a square on right side
while on the left side we have a smaller square and a triangle
Suppose the values written inside it are the weights of the shapes which are making it stable
So
Total on RHS = Total on LHS
Now Total on RHS = Value of bigger square
=
Total on LHS = Value of smaller sqaure + Value of triangle
=
Now we know to make this image a balanced one as shown n the figure
Total on RHS = Total on LHS
putting values gives us
=
which is the required equation