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Arturiano [62]
3 years ago
11

Help me, im breaking down.

Mathematics
2 answers:
denpristay [2]3 years ago
5 0

Answer:

next year is the correct answer

Simora [160]3 years ago
3 0
The answer is B );(:):)):)2$2$)/2)
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Please help me out! I tried to do it but I got it wrong.
Anika [276]

This may or may not be right.

You know that they are a graduate, and the total number of graduates are 2610.

The amount of graduates receiving financial aid is 1879.


The probability that a graduate student is on financial aid is: 1879/2610 = 0.7199 or 72%

4 0
3 years ago
Evelyn can run 3 miles in 40 minutes. Which equation can be solved to find m, the number of miles Evelyn can run in 60 minutes?
inna [77]

Answer:

m= 4.5 miles

Step-by-step explanation:

Let the number of miles Evelyn can run be m and can be modeled by the equation below

m= kx

Where x Is the Minutes

When m= 3

x= 40

3= k40

k= 3/40

If x= 60

m=3/40(60)

m = (60*3)/40

m= 180/40

m= 4.5 miles

7 0
3 years ago
Write the equation of the line given the point (3,7) and m=5/3
adoni [48]

Answer:

y= \frac{5}{3}x+2

<h2><u><em>PLEASE MARK BRAINLIEST</em></u></h2>

8 0
3 years ago
Rewrite the given parametric equations in Cartesian from x(t) = 2t– 1 y(t) = 5t
docker41 [41]

Hi there!

\large\boxed{(-\frac{5}{3},-\frac{5}{3})}

We can begin by setting the two expressions equal to solve for t:

2t - 1 = 5t

Subtract 2t from both sides:

-1 = 3t

Divide both sides by 3:

t = -1/3

Plug in this value of t into x(t) and y(t):

x(-1/3) = 2(-1/3) - 1 = -2/3 - 1 = -5/3

y(-1/3) = 5(-1/3) = -5/3

Thus:

(-5/3, -5/3) are the corresponding coordinates.

7 0
3 years ago
A random sample of 85 adults found that the average calorie consumption was 2100 per day. Previous research has found a standard
denpristay [2]

Answer:

$15600

Step-by-step explanation:

Minimum number of samples can be calculated using the formula:

N≥(\frac{z*s}{ME})^2 where

  • N is the sample size
  • z is the corresponding z-score for 95% confidence level (1.96)
  • s is the standard deviation of the calorie consumption (450 cal.)
  • ME is the margin of error that the researcher is willing to accept. (50 cal)

N≥(\frac{1.96*450}{50})^2 =311.2

Therefore, minimum required sample size for 50 cal standard error in 95% confidence is 312

Since the survey costs $50 for each person then the survey costs minimum

50*312=$15600

5 0
3 years ago
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