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SOVA2 [1]
3 years ago
6

a circle is centered at the point -3,2) and passes through the point (1,5). The radius of the circle is blank units. The point (

-7, blank) lies on this circle
Mathematics
1 answer:
lianna [129]3 years ago
3 0
It's important that you share the complete question.  What is your goal here?  Double check to ensure that you have copied the entire problem correctly.

The general equation of a circle is x^2 + y^2 = r^2.  Here we know that the circle passes thru two points:  (-3,2) and (1,5).  Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.


Subst. the known values (of the first point) into this equation:  (-3)^2 + (2)^2 = r^2.  Then 9 + 4 = 13 = r^2.

Let's check this.  Assuming that the equation of this specific circle is 
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.

(1)^2 + (5)^2 = 13 is not true, unfortunately.

(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).

Check the original problem.  If it's different from that which you have shared, share the correct version and come back here for further help.



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Answer:

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Step-by-step explanation:

First, you remove the parentheses.

−20 − 15

Then, you simplify and you're done!

−35

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Answer:

12 x^4 + 18 x^3 - 9 x^2 thus D is the correct answer.

Step-by-step explanation:

Expand the following:

3 x^2 (4 x^2 + 6 x - 3)

3 x^2 (4 x^2 + 6 x - 3) = 3 x^2 (4 x^2) + 3 x^2 (6 x) + 3 x^2 (-3):

3 4 x^2 x^2 + 3 6 x^2 x - 3 3 x^2

3 (-3) = -9:

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3 4 x^2 x^2 + 18 x^3 - 9 x^2

3 x^2×4 x^2 = 3 x^4×4:

3×4 x^4 + 18 x^3 - 9 x^2

3×4 = 12:

Answer:  12 x^4 + 18 x^3 - 9 x^2

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