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Kaylis [27]
3 years ago
15

ASAP please I need help please

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
5 0
9x+18=90
9x=72
x=8
This is the answer for problem 10 above

Problem 11:
62+58= 120
180-120 =60
Therefore angle FEA is 60 degrees

59+ 61=120
180-120= 60
Therefore angle CHF is also 60 degrees
Rays:
EB and HD ; EA and HC are both parallel because they have equivalent degree angles

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In 1999, the student enrolment at a college was 13% more than it was in 1998. If the enrolment was 36,612 in 2000, which was 8%
Brilliant_brown [7]

Answer:

1998= 30,000 students

Step-by-step explanation:

Giving the following information:

In 1999, the student enrolment at a college was 13% more than it was in 1998. If the enrolment was 36,612 in 2000, which was 8% more than 1999, find the enrolment in 1998

<u>First, we need to determine the enrolment in 1999:</u>

1999= 36,612/1.08

1999= 33,900

<u>Now, we can find the enrolment in 1998:</u>

1998= 33,900/1.13

1998= 30,000

6 0
4 years ago
Compute the diameter of a circle with a circumference of 34 feet.
True [87]

We know that circumference = diameter * 3.14, so in order to find the diameter all we have to do is:

circumference/3.14 = diameter

So, we can plug in the value of the circumference:

34 / 3.14 = 10.82

The exact answer is 10.82.

The approximate answer is 11.

5 0
3 years ago
The UAE Hope Probe is between 22,000 Km and 44,000 KM away from mars. This means its between _____________m and ______________m.
Marina86 [1]

Answer:

This means it is between 22000000 m and 44000000 m.

Step-by-step explanation:

From the question, the UAE Hope Pobe is between 22 000 km and 44 000 km away from Mars.

Since,

1 000 m = 1 km

Then,

22 000 km = 22 000 x 1000 m

                   = 22000000 m

also,

44000 km = 44000 x 1000 m

                  = 44000000 m

Therefore, the Probe is between 22000000 m and 44000000 m.

6 0
3 years ago
12 pints 3 cups = ? cups *
Allushta [10]

Answer:15

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which statement is true regarding the graphed functions?
Vladimir79 [104]

let's analyze each case to determine the solution

<u>case 1)</u> f(0) = 2 and g(–2) = 0

For x=0-----> find the value of f(0) in the graph-----> f(0)=4

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 1) is false

<u>case 2)</u> f(0) = 4 and g(–2) = 4

For x=0-----> find the value of f(0) in the graph-----> f(0)=4

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 2) is false

<u>case 3)</u> f(2) = 0 and g(–2) = 0

For x=2-----> find the value of f(2) in the graph-----> f(2)=0

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 3) is true

<u>case 4)</u> f(–2) = 0 and g(–2) = 0

For x=-2-----> find the value of f(-2) in the graph-----> f(-2) is greater than 12

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 4) is false

therefore

<u>the answer is</u>

f(2) = 0 and g(–2) = 0-------> this statement is true


6 0
4 years ago
Read 2 more answers
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