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strojnjashka [21]

3 years ago

8

according to government birth statistics the probability of women giving birth to twins is 0.015 what is the probability of not

having twins?

1 answer:

snow_lady [41]3 years ago

4 0

1-0.015=0.985 is the probability expressed as a decimal

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Jasmine has taken an online boating course safety course and now completing her end-of-course exam . As she answers each questio

melomori [17]

Answer:

80

Step-by-step explanation:

20 percent is 16 questions

then 100/20=5

5 times 16 is 80

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Find the solution for 5x-7y=17 and 9x-7y=-11

ad-work [718]

Step-by-step explanation:

Refer to attachment.

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The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out t

yulyashka [42]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

C

b

C

c

C

d

A

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 0.5 \ in$

Generally the Null hypothesis is $H_o : \mu = 0. 5 \ in$

The Alternative hypothesis is $H_a : \mu \ne 0.5 \ in$

Considering the parameter given for part a

The sample size is n = 15

The test statistics is t = 1.66

The level of significance $\alpha = 0.05$

The degree of freedom is evaluated as

$df = n- 1$

$df = 15- 1$

$df = 14$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145$

We are making use of this $t_{\frac{\alpha }{2} }$ because it is a one-tail test

Looking at the value of t and $t_{\frac{\alpha }{2} }$ the we see that $t < t_{\frac{\alpha }{2} }$ so the null hypothesis would not be rejected

Considering the parameter given for part b

The sample size is n = 15

The test statistics is t = -1.66

The level of significance $\alpha = 0.05$

The degree of freedom is evaluated as

$df = n- 1$

$df = 15- 1$

$df = 14$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145$

Looking at the value of t and $t_{\frac{\alpha}{2} ,df }$ the we see that t does not lie in the area covered by $t_{\frac{\alpha}{2} , df }$ (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part c

The sample size is n = 26

The test statistics is t = -2.55

The level of significance $\alpha = 0.01$

The degree of freedom is evaluated as

$df = n- 1$

$df = 26- 1$

$df = 25$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787$

Looking at the value of t and $t_{\frac{\alpha }{2} }$ the we see that t does not lie in the area covered by $t_{\alpha , df }$ (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part d

The sample size is n = 26

The test statistics is t = -3.95

The level of significance $\alpha = 0.01$

The degree of freedom is evaluated as

$df = n- 1$

$df = 26- 1$

$df = 25$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787$

Looking at the value of t and $t_{\frac{\alpha}{2} }$ the we see that t lies in the area covered by $t_{\alpha , df }$ (i.e the area from -2.787 downwards on the normal distribution curve ) hence we reject the null hypothesis

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3 years ago

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maks197457 [2]

Answer:

1. D

2. D

Step-by-step explanation:

5 0

3 years ago

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Write a rule for the function that shifts every point in the plane 10 units down and 4 units to the right

ElenaW [278]

Answer:

Substitute y with y+10 and x with x-4.

Step-by-step explanation:

To shift every point in the plane 10 down you have to substitute y with y+10 and to shift every point in the plane 4 units right you have to substitute x with x-4.

Suppose the origin of function on the plane is (0,0) now we have to make the origin (4,-10).

first (x,y)=(0,0)

When we substitute x and y

(x-4,y+10)=(0,0)

x-4=0

x=4

y+10 = 0

y= -10

Now the origin is (4,-10).

Hence the function is shifted 10 units down and 4 units right.

8 0

3 years ago