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3 years ago

Select the true statements about the number line

Mathematics

2 answers:

Elden [556K]3 years ago

5 0

The answer is A>2
as A is -1.5

lukranit [14]3 years ago

3 0

Answer:

A. Point A > -2

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Find the range and the first and third quartiles for the data set 45,42,86,13,74,47,46

Lesechka [4]

The range = highest value - lowest = 86 - 13 = 73.

arrange in order:-

13 42 45 46 47 74 86

median = 46

First quartile = (42 + 45) / 2 = 43.5

third quartile = (74 - 47) / 2 = 60.5

6 0

3 years ago

Y = 15x - 40 when x = 3 function and solution??

kirza4 [7]

The answer is 5, then you double check to make sure the solution is correct

5 = 15(3) - 40

5 = 45 - 40

5 = 5

6 0

4 years ago

Read 2 more answers

out of 1200 student served at lunch 660 of the students get hamburgers what is the percent of people who got hamburgers

Mars2501 [29]

Answer:

45% of students got hamburgers :)

Step-by-step explanation:

3 0

3 years ago

Combine and Simplify: 48 (1/4x - 1/3y - 2/6x - 3/8y - 2/3 WRITE 2 WAYS!

Bezzdna [24]

Answer:

Combining and simplifying $48(\frac{1}{4}x-\frac{1}{3}y-\frac{2}{6}x-\frac{3}{8}y-\frac{2}{3})$ we get $\mathbf{-4x-34y-32}$ or we can write as $\mathbf{48(\frac{-x}{12} -\frac{17y}{24}- \frac{2}{3})}$

Step-by-step explanation:

We need to combine and simplify

$48(\frac{1}{4}x-\frac{1}{3}y-\frac{2}{6}x-\frac{3}{8}y-\frac{2}{3})$

First we will combine like terms and then perform the mathematical operations like addition or subtraction.

Like terms: terms having same variable

$48(\frac{1}{4}x-\frac{2}{6}x-\frac{1}{3}y-\frac{3}{8}y-\frac{2}{3})$

Now we take LCM of like terms

$=48(\frac{1}{4}x-\frac{2}{6}x-\frac{1}{3}y-\frac{3}{8}y-\frac{2}{3})\\=48(\frac{x*3-2x*2}{12} +\frac{-y*8-3y*3}{24}- \frac{2}{3})\\=48(\frac{3x-4x}{12} +\frac{-8y-9y}{24}- \frac{2}{3})\\=48(\frac{-x}{12} +\frac{-17y}{24}- \frac{2}{3})\\=48(\frac{-x}{12} -\frac{17y}{24}- \frac{2}{3})$

Now, we can multiply 48 with terms inside the bracket.

we can simplify the terms if they are both divisible by same number.

$=48(\frac{-x}{12} -\frac{17y}{24}- \frac{2}{3})\\=48(\frac{-x}{12} )-48(\frac{17y}{24})-48(\frac{2}{3}))\\=-4x-34y-32$

So, Combining and simplifying $48(\frac{1}{4}x-\frac{1}{3}y-\frac{2}{6}x-\frac{3}{8}y-\frac{2}{3})$ we get $\mathbf{-4x-34y-32}$ or we can write as $\mathbf{48(\frac{-x}{12} -\frac{17y}{24}- \frac{2}{3})}$

6 0

3 years ago

5.5-x=-4.5-x. how do you solve this?

rodikova [14]

The answer to this will be 10x

6 0

3 years ago