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borishaifa [10]
3 years ago
12

Evaluate (625/16)^1/4.Please answer correctly as soon as possible​

Mathematics
1 answer:
podryga [215]3 years ago
4 0

Answer:

=  \frac{5}{2}  = 2 \frac{1}{2}

Step-by-step explanation:

( \frac{625}{16}  {)}^{ \frac{1}{4} }  \\  \sqrt[4]{ \frac{625}{16} }  =  \frac{ \sqrt[4]{625} }{ \sqrt[4]{16} }   \\  \frac{ \sqrt[4]{ {5}^{4} } }{ \sqrt[4]{16} }  =  \frac{ \sqrt[4]{ {5}^{4} } }{ \sqrt[4]{ {2}^{4} } }  =  \frac{5}{2}

\boxed{\green{=  \frac{5}{2}  = 2 \frac{1}{2}}}

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Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2
fredd [130]

Answer:

Both get the same results that is,

\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

Step-by-step explanation:

Given :

\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

and initial population,

\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]

a) - After two times, we will find in each position.

P_2=[P].[M]^2=[P].[M].[M]

M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

     =\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]

b) - With in migration process, 500 people are numbered. There will be after a long time,

After\;inifinite\;period=[M]^n.[P]

Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

                                   =\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

4 0
3 years ago
Please help 5 questions I need help
creativ13 [48]

Answer:

1. <2, <7

2. 58

3. 78

4. a and b

h5. <2 and <7 ( i think this is the same question as the first one)

Step-by-step explanation:

2. 2x + 7 = 123 (you have to make them equal to each other because they are consecutive interior angles)

2x + 7 = 123, subtract 7

2x = 116, divide 2 for both sides to make x by itself

x = 58

3. 78 because of consecutive interior angles

4 0
3 years ago
A cylindrical tank is filled with 66.85 mm3 of fuel. The area of the base of the cylinder is 15 mm2. What is the height of the f
Rashid [163]
Volume = (Area of the base)x(Height)
66.85 = 15(H)
66.85/15 = H
H = 4.4567

The height is 4.4567mm.
3 0
3 years ago
Tri-County Utilities, Inc., supplies natural gas to customers in a three-county area. The company purchases natural gas from two
Sav [38]

Answer:

The network model is attached.

Step-by-step explanation:

Total Demand from each Gas Company are:

Southern Gas, 500 units;

Northwest Gas, 400 units.

Total Supplies to each County are:

Hamilton County, 400 units;

Butler County, 200 units;

Clermont County, 300 units.

The distribution costs per unit (in thousands of dollars) are as follows

-----------Hamilton-- Butler-- Clermont

Southern Gas--- 10 ---20--- 15

Northwest Gas ----12 ----15---- 18

The network representation of these information is given in the attachment.

3 0
3 years ago
Tom opens a bank account and makes an initial deposit of 500$. Then banker tells Tom that he is going to receive an annual rate
Arturiano [62]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$500\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &15 \end{cases} \\\\\\ A=500\left(1+\frac{0.06}{1}\right)^{1\cdot 15}\implies A=500(1.06)^{15}\implies A\approx 1198.28

5 0
2 years ago
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