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2 years ago

Help i have 3 minutes

Mathematics

1 answer:

Zepler [3.9K]2 years ago

5 0

Answer: [2 green dot], [4 red dots]

Step-by-step explanation:

Pattern for red is 4 red dots, 3 red dots, 4 red dots, 3 red dots...

Pattern for green dots is 16, 11, 7, 4, 2, 0, -1... <em>The pattern here is, starting at 16, subtract 5, then subtract 4, then subtract 3, then subtract 2...</em>

16 - 5 = 11

11 - 4 = 7

7 - 3 = 4

4 - 2 = 2

2 - 2 = 0

0 - 1 = -1

Hope this helps!

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Find the output, b, when the input, a, is 6.<br> b = -1-7a<br> b=

natka813 [3]

The answer is -43
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B=-1-42
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3 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

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3 years ago

Question 2

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Answer:

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<h3>Imaginary numbers </h3>

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Given the rational number √-4 for instance, this will result in complex number or imaginary number since it is a negative number.

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