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3 years ago

Given f(x) = x2−2x+2, find the value(s) for x such that f(x)=37.

Mathematics

1 answer:

wel3 years ago

7 0

Answer:

Step-by-step explanation:

2x-2×2=8 porque vas sumando

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WHAT IS THE ANSWER TO -2(y-3)=22

Eva8 [605]

-2(y-3)=22
-2y+6=22
-2y=16
y=-8

8 0

3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago

ACDF,BE is a mid segment what is x?

Ksenya-84 [330]

Answer:

X= 15

Step-by-step explanation:

the above equation will be used to determine the value of x.

6x-12= 2x+20+18

6x-2x = 20+12+18

4x= 60.

X= 60/4

X= 15

x = 15

7 0

3 years ago

Solve.

Alecsey [184]

Answer:

Step-by-step explanation:

Square root of 100 is 10

7 0

3 years ago

Read 2 more answers

14/16

Alla [95]

Answer:

2x + 3y > 100

x + y = 40

Step-by-step explanation:

This is the answer because it shows the price of each and the combined products equaling more than 100 dollars, and the bottom one shows that the combined total of jewelry can not exceed 40 pieces.

5 0

2 years ago

Given​ f(x) = x2−2x+2​, find the​ value(s) for x such that ​f(x)=37.

Given f(x) = x2−2x+2, find the value(s) for x such that f(x)=37.