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wariber [46]
3 years ago
8

Given​ f(x) = x2−2x+2​, find the​ value(s) for x such that ​f(x)=37.

Mathematics
1 answer:
wel3 years ago
7 0

Answer:

8

Step-by-step explanation:

2x-2×2=8 porque vas sumando

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Factor each expression 36abc +54ad
olya-2409 [2.1K]

Answer:

18a(2bc + 3d)

Step-by-step explanation:

36abc + 54ad

Step 1: Find the Highest Common Factor of each

36abc = 2×2×3×3×a×b×c = 18a × 2bc

54ad = 2×3×3×3×a×d = 18a × 3d

HCF = 2×3×3×a = 18a

Step 2: Factor out with HCF

18a(2bc + 3d)

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4 years ago
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3 years ago
_11] If the radius of a circle is 5, what is the circumference?
ArbitrLikvidat [17]

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Step-by-step explanation:

A circle with a radius of 5 units has a circumference of 31.416 units.

8 0
3 years ago
A detective finds a victim of murder at 9 am. At that time, the temperature of the body is 90.3 degrees F. One hour later, the b
LekaFEV [45]

Answer:

Step-by-step explanation:

Given

at 9 am temperature of the body is 90.3^{\circ}F

1 hr later temperature 89^{\circ}F

Temperature of room T=68^{\circ}F

According to newtons law

\frac{\mathrm{d} T}{\mathrm{d} t}=-k\left ( T-T_{room}\right )

\frac{\mathrm{d} T}{\mathrm{d} t}=-k\left ( T-68\right )

\frac{dT}{T-68}=-kdt

Integrating

=\int \frac{dT}{T-68}=-kdt

\ln |T-68|=-kt+c

T-68=Ae^{-kt}

Now at 9 am i.e. t=0,

90.3=A+68

A=22.3

At 10 am i.e. t=1 hr T=89

89-68=22.3e^{-k}

e^{-k}=21

k=0.06006

Temperature of Normal human body is T=98.6 ^{\circ}F

98.6-68=e^{-0.06006t}

30.6=e^{-0.06006t}

Taking log both sides

t=-5.27

i.e. 5 hr and  16.2 min

i.e. victim murdered at 3 am and 43.8 min

7 0
3 years ago
What is 60% of 160?
Ilya [14]

Answer:

96

Step-by-step explanation:

60/100 x 60 = 96

6 0
3 years ago
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