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3 years ago

Which expression gives the same result as shown problem?

Mathematics

1 answer:

sineoko [7]3 years ago

8 0

The first choice gives you the same result. The factor of 5 can be removed to the outside of the summation symbol.

$5\sum\limits_{i=0}^{4}{\left(\dfrac{1}{3}\right)^{i}}$

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So how yall doing so whats 200 times 3/4 =

horrorfan [7]

Answer:

200 times 3/4 is 150

Hope this help!

Brainliest??

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2 years ago

HELP PLEASE

777dan777 [17]

1 worker=1/5 grass per hour
6 workers

number of workers times work each worker does times time needed=total work done
5 times ? times 1=1 lawn
?=1/5 lawn
1 worker does 1/5 lawn in 1hour

6 workers
work is 1/5
time=?
total work=1

6 times 1/5 times ? =1
6/5 times ?=1
times 5/6 both sides
?=5/6

it takes 5/6 hour or 50 minutes

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2 years ago

HELP ME AGAIN PLEASE I BEG

BartSMP [9]

Answer:

Both of your answers are correct

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Show that -11.0027 is a rational number?

Papessa [141]

Answer:

it's a rational number

Step-by-step explanation:

let me know if this helps :)

dont know if this is what you want but here...

A rational number is a number that is of the form p/q where p and q are integers and q is not equal to 0. The set of rational numbers is denoted by Q. In other words, If a number can be expressed as a fraction where both the numerator and the denominator are integers, the number is a rational number.

6 0

2 years ago

Población de alces. Se introducen cíen alces en una reserva zoológica, cada uno de un año de edad. El número N(t) de animales vi

frutty [35]

Answer:

El número de animales vivos después de 1, 5 y 10 años es 90, 60 y 35 respectivamente.

Step-by-step explanation:

Sabes que el número N(t) de animales vivos después de t años se predice mediante N(t) = 100* $0.9^{t}$

Para estimar el número de animales vivos después de, por ejemplo, 1 año debes simplemente reemplazar el tiempo t por el tiempo correspondiente, en este caso 1 año:

N(1) = 100* $0.9^{1}$

Resolviendo:

N(1) = 100* $0.9^{1}$ = 100*0.9= 90

De manera similar, podes estimar el número de animales vivos después de 5 y 10 años. Esto es, reemplazas t por 5 años:

N(5) = 100* $0.9^{5}$ = 100*0.59049= 59.049≅ 60

y t por 10 años:

N(10) = 100* $0.9^{10}$ = 100*0.3487= 34.86 ≅ 35

<u><em>El número de animales vivos después de 1, 5 y 10 años es 90, 60 y 35 respectivamente.</em></u>

6 0

3 years ago