#<br> #1 Fill in the missing values<br> in the table below:

Jen picked 3/4 of a gallon of strawberries in half an hour. If she keeps picking strawberries at the same rate, how many gallons

scoray [572]

Well following the directions you have provided me I would say that Jen will have 3 Gallons of strawberries. Work: So the fraction 3/4 can be converted into decimals which is .75 and since she got that many in half and hour ( 30 minutes) we can do two set of .75 for each hour, after we do the math we end up with 4 sets in total of .75 since she had 2 hours to work. Equation .75*4=3

I hope this helped you out!

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4 years ago

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An electronic product contains 40 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

neonofarm [45]

Answer:

There is a 33.10% probability that there is at least one defective integrated circuit.

Step-by-step explanation:

For either integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem

The electonic product contains 40 integrated circuits, so $n = 40$ .

The probability that any integrated circuit is defective is 0.01, so $\pi = 0.01$

What is the probability that there is at least one defective integrated circuit?

Either there is at least one defective integrated circuit, that is probability $P(X > 0)$ , or there are no defective integrated circuits, that is probability $P(X = 0)$ . The sum of these probabilities is decimal 1. We want to find $P(X>0)$ .