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Ilya [14]
3 years ago
5

Harry and Selma start driving from the same location. Harry drives 65 mi north while Selma drives 72 mi east. How far apart are

Harry and Selma when they stop? (Assume Harry and Selma are driving at the same speed.)
Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

97 miles apart

Step-by-step explanation:

We can use the Pythagorean Theorem to find the distance between Harry and Selma, which their respective distances from the same starting location become the legs of a right triangle. We find the distance between Harry and Selma by solving for the hypotenuse:

a^2+b^2=c^2

65^2+72^2=c^2

4225+5184=c^2

9409=c^2

\pm97=c

c=\pm97

Because distance is always positive, then the distance between Harry and Selma when they stop is 97 miles.

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Step-by-step explanation:

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Soft drinks are being purchased in case of 24. If there are 1008 soft drinks to packed,how many cases are needed?​
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42 Cases.

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3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

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