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levacccp [35]
3 years ago
8

A video game that usually costs $30.65 is marked down 60%. Kelvin determined that the new price of the game would be $18.39. Loo

k at Kelvin’s work and find his error.
($30.65)(0.60) = $18.39 <----kelvins work
Mathematics
2 answers:
vlada-n [284]3 years ago
8 0

Answer:

Sample Response: Kelvin should have subtracted $18.39 from $30.65 to find the marked down price. He could also have multiplied the original cost by 40% to find the sale price of $12.26.

sladkih [1.3K]3 years ago
6 0
The error.....Kelvin just figured the 60% markdown cost...not the final price

the final price would be : 30.65 - 0.60(30.65) = 30.65 - 18.39 = 12.26
so 12.26 is the final price

or another way to do this is : if it is marked down 60%, then u r actually paying 40%......0.40(30.65) = 12.26
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∠A and ∠B are vertical angles. If ∠A=8x+14 and ∠B=2x+50, what is m∠B?
Maslowich

Answer:

∠B = 62°

Step-by-step explanation:

Because ∠A and ∠B are vertical angles they are equal hence we can write

∠A = ∠B

8x + 14 = 2x + 50

Now we have to solve for x

To do so, subtract 2x on both sides of the equation:

6x + 14 = 50

Now, subtract 14 on both sides of the equation

6x = 36

Now, divide 6 on both sides of the equation

x = 6

To find m∠B you have to you have to plug in x = 6 back into the ∠B equation

∠B = 2(6) + 50

∠B = 62°

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284.115 simplified in to a number
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Step-by-step explanation:

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A manufacturer of tires wants to advertise a mileage interval that ex-cludes no more than 10% of the mileage on tires he sells.
Sergio039 [100]

Answer:

This mileage interval is from 30120 miles and higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

All he knows is that, for a large number of tires tested, the mean mileage was 25,000 miles, and the standard deviation was 4000 miles. This means that \mu = 25000, \sigma = 4000.

A manufacturer of tires wants to advertise a mileage interval that ex-cludes no more than 10% of the mileage on tires he sells. What interval wouldyou suggest?

The lower end of this interval is X when Z has a pvalue of 0.90.  That is Z = 1.28.

So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 25000}{4000}

X - 25000 = 4000*1.28

X = 30120

This mileage interval is from 30120 miles and higher.

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Answer:

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Answer:

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Step-by-step explanation:

1. 4x - 7y =  - 5

4x =  - 5 + 7y

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y E R

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2. 3x - 2y =  - 7

3x =  - 7 + 2y

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