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3 years ago

The graph only goes up to 10 FYI

Mathematics

1 answer:

Otrada [13]3 years ago

3 0

Answer:

This is the first line.

point one (0,-2)

point two (5,-5)

This is the second line.

point one (0,6)

point two (1,7)

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X^2+17x=-42 <br> how do i find the solutions to this problem?

ELEN [110]

photo math duhhhhhhhhhhhhhhhhhhhh

3 0

3 years ago

Solve for all values of p:

Alchen [17]

Answer:

p = - 5, p = - 1

Step-by-step explanation:

Given

$\frac{3p}{p-5}$ - $\frac{2}{p+3}$ = $\frac{p}{p+3}$

Multiply through by the LCM of (p - 5)(p + 3)

3p(p + 3) - 2(p - 5) = p(p - 5) ← distribute parenthesis

3p² + 9p - 2p + 10 = p² - 5p

3p² + 7p + 10 = p² - 5p ( subtract p² - 5p from both sides )

2p² + 12p + 10 = 0 ← divide through by 2

p² + 6p + 5 = 0 ← in standard form

(p + 1)(p + 5) = 0 ← in factored form

Equate each factor to zero and solve for p

p + 1 = 0 ⇒ p = - 1

p + 5 = 0 ⇒ p = - 5

3 0

2 years ago

Convert 638.9569046 hours to minutes

choli [55]

38337.414276 minutes

8 0

2 years ago

What is the difference in simplest form? <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%5E2%2B3n%2B2%7D%7Bn%5E2%2B6n%2B8%7D-%5

Paha777 [63]

$\bf \cfrac{n^2+3n+2}{n^2+6n+8}-\cfrac{2n}{n+4}\implies \cfrac{n^2+3n+21}{(n+4)(n+2)}-\cfrac{2n}{n+4}
\\\\\\
\textit{so our LCD will just be (n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(n+2)(2n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(2n^2+4n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~2n^2-4n}{(n+4)(n+2)}
\implies 
\cfrac{-n^2-n+2}{(n+4)(n+2)}
\\\\\\
\cfrac{-(n^2+n-2)}{(n+4)(n+2)}\implies \cfrac{-\underline{(n+2)}(n-1)}{(n+4)\underline{(n+2)}}\implies \cfrac{-(n-1)}{n+4}\implies \cfrac{1+n}{n+4}$

3 0

3 years ago

The distance traveled varies directly with the time of travel. If

never [62]

Answer:

The constant is 10 for every 1 seconds the time traveled is 10 meters

Step-by-step explanation:

7 0

2 years ago