Enter an equation in point-slope form for the line. Slope is 9 and (−3, −1) is on the line.
1 answer:
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Answer:
∠XDQ : 41°
∠UXD: 139 °
Step-by-step explanation:
Allow me to rewrite your answer for a better understanding and please have a look at the attached photo.
<em>A segment XD is drawn in rectangle QUAD as shown below. </em>
<em>What are the measures of ∠XDQ and ∠UXD ? </em>
My answer:
As we can see in the photo, ∠ADX = 49° and ∠ADU =90°
=> ∠XDQ = ∠ADU - ∠ADX
= 90° - 49° = 41°
In the triangle ADX, we can find out the angle of ∠DXA
= 180° - ∠DAX - ∠ADX
= 180° - 90° - 49°
= 41°
=> <em>∠UXD = </em>180° - ∠DXA (Because UA is a straight line)
=180° - 41°
= 139 °
