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2 years ago

How much did the roses cost?

Mathematics

1 answer:

Lubov Fominskaja [6]2 years ago

6 0

Answer: The roses costed $9

Step-by-step explanation:

3 multiplied by 3 equals 9

1 multiplied by 6 equals 6

9+6=15

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Given the diagram below what is the length of segment EF

frosja888 [35]

Answer:

C is the closest.,

Step-by-step explanation:

I am assuming that the 2 trapezoids CBEF and EFDA are similar (they are similar if the 3 horizontal lines are parallel).

Corresponding sides are in the same ratio , so:

3.4 / EF = EF / 7.6

EF^2 = 3.4 * 7.6 = 25.84

EF = 5.08

6 0

3 years ago

Read 2 more answers

Which is losing the fewest? 8 -2 5 -7

PilotLPTM [1.2K]

-7 is losing the fewest as it is the smallest number, and the number that is to the left of the number line.

5 0

2 years ago

3x + 8 + 4x = -8(x - 6) - 8(13x + 5)

ollegr [7]

3x+8+4x=-8x+48–104x–40
7x+8=-112x+8
-7x -7x
8=-119x+8
-8 -8
0=-119x
0=x

4 0

2 years ago

Read 2 more answers

The Big Telescope Company sells circular mirrors. Their largest mirrors have radii of 5 meters and their smallest mirrors have r

pogonyaev

Answer: 1:5

Step-by-step explanation:

Given: The cost of every mirror is proportional to the cube of the mirror's radius.

i.e. $\dfrac{\text{Cost of smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{(\text{radii of smallest mirror}^3)}{\text{(radii of largest mirror)}^3}$

Their largest mirrors have radii of 5 meters and their smallest mirrors have radii of 1 meter.

Then,

$\dfrac{\text{Cost of smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{1^3}{(5)^3}=\dfrac{1}{125}$

The ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors will be:

$\dfrac{\text{Cost of 25 smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{25\times 1}{125}=\dfrac{1}{5}$

Hence, the ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors = 1:5 .

5 0

2 years ago

Please help me solve this!!

Mice21 [21]

Answer:

Abelito had the greater average speed

Step-by-step explanation:

Given

Bobby:

$Distance =4\ miles$

$Time = 30\ minutes$

Abelito

$Distance = 10\ miles$

$Time = 48\ minutes$

Required:

Who had a greater average speed

Average speed (S) is calculated as:

$S = \frac{Distance}{Time}$

We will make use of mph (miles per hour) as the unit of speed.

For Bobby:

$S_B = \frac{4\ miles}{30\ minutes}$

Convert minute to hour

$S_B = \frac{4\ miles}{0.5\ hr}$

$S_B = 8mph$

For Abelito

$S_A = \frac{10\ miles}{48\ minutes}$

Convert minute to hour

$S_A = \frac{10\ miles}{0.8\ hr}$

$S_A = 12.5mph$

By comparison: 12.5mph > 8mph

Hence: Abelito had the greater average speed

5 0

2 years ago