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2 years ago

SUBTRACTION: EXPRESS THE ANSWER IN STANDARD FORM (-5x^2 + x + 1) - (x^3 + 6x^2 - 4x)

Mathematics

1 answer:

svp [43]2 years ago

8 0

Answer:

-x³ - 11x² + 5x + 1

Step-by-step explanation:

In case you cant read it it says: -x^3 - -11x^2 + 5x + 1

Hope this helps!

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Number 19 and number 20 please

aev [14]

F(-1)=3(-1)-5=-3=5=-8

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3 years ago

How do you do 137 ÷ 7 in a area model

aliya0001 [1]

Hey,

If you were to divide 137/7 it would be it would be 19 or if you wont a decimal it would be 19.5

I Hoped that Helped

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3 years ago

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Solve for x <br>please I need the answer the picture shows the question

ozzi

Answer:

15inch

Step-by-step explanation:

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2 years ago

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the circumference of the circle shown below is 54 centimeters. which expression gives the length in centimeters of XY?

g100num [7]

Answer:

The correct option is C

Step-by-step explanation:

Given the circumference of circle which is 54 cm and also the measure of arc XY is 120°

we have to find the expression for arc length of XY

The arc length can be calculated by the formula

$\frac{\theta}{360}\times 2\pi r$

$\frac{\theta}{360}\times circumference$

$\frac{120}{360}\times 54$

Hence, option C is correct

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3 years ago

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HELP ASAP PLZZZZ

Tcecarenko [31]

QUESTION 1

The given system of equations is

$3d - e = 7...eqn(1)$
$d + e = 5...eqn(2)$

To solve by linear combination, we add equation (1) to equation (2) to get,

$3d + d= 7 + 5$

$4d = 12$

We divide through by 4 to obtain,

$d = \frac{12}{4}$

$d = 3$

We put d=3 into equation (2) to get,

$3+ e = 5$

$e = 5 - 3$

$e = 2$

$\boxed {The \: solution \: is \: (3, 2)}$

QUESTION 2

The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)

To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

$4x - 3x = 5 - 3$

This implies that,

$x = 2$

Put x=3 into equation (1) to get,

$4(2) + y = 5$

$8+ y = 5$

$y = 5 - 8$

$y = - 3$

The solution is

$(2,-3)$

QUESTION 3

We want to solve the system;

a – 2b = –2 ....eqn(1)

2a + 2b = 14...eqn(2)

by linear combination.

We need to add equation (1) to equation (2) to eliminate b.

This implies that,

$2a + a = 14 + - 2$

Simplify,

$3a = 12$

Divide both sides by 3 to get,

$a = 4$
Put a=4 into equation (2) to obtain,

$2(4) + 2b = 14$

$8 + 2b = 14$
$2b = 14 - 8$

$2b = 6$

$b = 3$

The ordered pair in the form (a, b) is

$(4,3)$

QUESTION 4

The given system of equations is

11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)

We subtract equation (2) from equation (1) to get,

$11x - 3x = 18 - 2$

$8x = 16$

$x = 2$

Put x=2 into equation (2) to obtain,

$3(2) + 4y = 2$

This implies that,

$6 + 4y = 2$

$4y = 2 - 6$

$4y = - 4$

$y=-1$

The correct answer is (2,-1).

QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2

We add the two equations to eliminate e.

This implies that,

$2d + d = 8 + 4$

$3d = 12$

We divide both sides by 3 to get,

$d = 4$

We put d=4 into equation (2) to get,

$4 - e = 4$

$- e = 4 - 4$

$- e = 0$

$e = 0$

The solution is

$(4,0)$

7 0

3 years ago