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Vilka [71]
3 years ago
6

How do you solve this? x/4 divided by_ =x

Mathematics
1 answer:
Ahat [919]3 years ago
4 0

Answer:

good morning baby girl I hope you had fun with you want me money I'm

Step-by-step explanation:

find the attachment of the attachment good morning baby girl I wanted to know how many people will be

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Answer: question 5 is C

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Step-by-step explanation:

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kicyunya [14]
Y=-4/3x+300 hope this helps
4 0
4 years ago
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In parallelogram ABCD , diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E, AE = 3x - 5, and CE = x + 11.
german

Answer:

38

Step-by-step explanation:

For the case of a parallelogram, when the diagonals ( in our case AC & BD) are intersected, they are basically bisected ( divided into two equal halves ). Therefore when the diagonals intersect at point E, we can say that the diagonal AC is divided in two equal halves which in our case are AE and CE. since AE and CE are equal , we can say that,

AE= CE \\or\\3x-5 = x+11 ---- (1)\\now  solving (1)  for x, \\3x-x=11+5\\2x=16\\x=8-----> (2)\\\\as      \\ AC = AE+CE\\AC = 3x-5+x+11\\AC = 4x+6\\\\\\from (2)\\\\\\AC= 4(8)+6\\AC = 32+6\\AC = 38\\\\since AC = BD ( Diagonals     are    of same Length )\\therefore \\BD =38

5 0
4 years ago
Please help AS LEVEL c2 tell me how to work out
Korolek [52]
\bf [1-tan(\theta)][2sin(\theta)+1]=0\implies 
\begin{cases}
1-tan(\theta)=0\\\\
1=tan(\theta)\\\\
tan^{-1}(1)=\theta\\\\
\qquad \frac{\pi }{4},\frac{5\pi }{4}\\
----------\\
2sin(\theta)+1=0\\\\
2sin(\theta)=-1\\\\
sin(\theta)=\frac{-1}{2}\\\\
sin^{-1}\left(-\frac{1}{2}  \right)=\theta\\\\
\qquad \frac{7\pi }{6},\frac{11\pi }{6}
\end{cases}
3 0
4 years ago
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