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cestrela7 [59]
2 years ago
7

What equation can fix this?

Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
4 0

fix what wheres the photo of it idsi

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Please help with this anyone
tresset_1 [31]
You distribute the 4 to both x and 5. 4 times x is 4x and 4 times 5 is 20. Divide both sides by 4. X=5
5 0
2 years ago
Translate 3(x-y)=2y+9 into a verbal sentence
dezoksy [38]

Answer:

3 times x then minus 3 times y equal 2y plus 9

Step-by-step explanation:

Not sure if it works......

that's the verbal sentence (which is not formal sentence) i can think of now......

7 0
2 years ago
21. You purchase 100 shares of Ravioli Den for $45 per share. One year later, you sell the shares
kicyunya [14]

Answer: 20%

100 shares at $45each cost 100*45 = $4500

After a year, he sold the share at the rate if $52 each and it cost 52*100 = 5200

He received dividend of $2 on each dollars meaning 100*2 = $200

So,

$5200+200 = 5400

Profit = $5400 - 4500 = 900

%profit = 900*100 / 4500 = 20

4 0
3 years ago
There is 20% of a 50lb. Bag of dog food left. How much has been used?
Nitella [24]

Answer:

40 lbs was used

Step-by-step explanation:

If there is 20% left, that means 80% was used

50 *80%

Change to decimal form

50 *.80

40

40 lbs was used

5 0
2 years ago
How do you solve this: In ?PQR, PQ = 39 cm and PN is an altitude. Find PR if QN = 36 cm and RN = 8 cm.
ikadub [295]

Answer:

PR = 17 cm


Step-by-step explanation:

Given  :

In ΔPQR,

PQ = 39 cm

PN is an altitude.

QN = 36 cm

RN = 8 cm.

To Find : Length of PR

Solution :

Since we are given that PN is an altitude .

So, PN divides ΔPQR in two right angled triangles named as ΔPQN and ΔPRN. (Refer attached file)

So, first we find Length of PN in ΔPQN using Pythagoras theorem i.e.

(Hypotenuse)^{2}=(Perpendicular)^{2} +(Base)^{2}

(PQ)^{2}=(PN)^{2} +(QN)^{2}

(39)^{2}=(PN)^{2} +(36)^{2}

1521=(PN)^{2} +1296

1521 -1296=(PN)^{2}

225=(PN)^{2}

\sqrt{225} = PN

15 = PN

Thus, Length of PN = 15cm

Now to find length of PR we will use Pythagoras theorem in ΔPRN.

(PR)^{2}=(PN)^{2} +(NR)^{2}

(PR)^{2}=(15)^{2} +(8)^{2}

(PR)^{2}=225 +64

(PR)^{2}=289

PR= \sqrt{289}

PR= 17

Hence the length of PR = 17 cm



3 0
3 years ago
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