Answer:
The fourth pair of statement is true.
9∈A, and 9∈B.
Step-by-step explanation:
Given that,
U={x| x is real number}
A={x| x∈ U and x+2>10}
B={x| x∈ U and 2x>10}
If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.
Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.
So, 5∉A, and 5∉B.
If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.
Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.
So, 6∉A, and 6∈B.
If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.
Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.
So, 8∉A, and 8∈B.
If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.
Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.
So, 9∈A, and 9∈B.
The area of the sector will also be 70/360
Sector area = 70/360 • pir^2
= 7/36 • pi • 8^2
A= 112/9 • pi
A= 39.1 inch^2
Answer:6√3
Explanation:Before we begin, remember the following:
Now, for the given:75 can be written as 25*3
This means that:
Applying the above concept, we can find that:
Now, we know that:
√25 = 5 (we ignored the negative value)
This means that:
√75 = 5√3
Finally, we can compute the needed sum as follows:
√75 + √3 = 5√3 + √3 = 6√3
Hope this helps :)
Answer:
cosine of angle a = 8/17
Step-by-step explanation:
Hello there!
Remember these are the trigonometric ratios
SOC CAH TOA
Sine = Opposite over Hypotenuse (SOH)
Cosine = Adjacent over Hypotenuse (CAH)
Tangent = Opposite over Adjacent (TOA)
And we are asked to find the Cosine of angle A
Remember cosine is adjacent over hypotenuse
Hypotenuse - The longest side
Adjacent - the side that's not the hypotenuse nor the opposite
The adjacent side length of angle A is equal to 8 and the hypotenuse is equal to 17
so the cosine of angle a = 8/17
Answer & Explanation:
To find the direction cosines of the vector a is need to divided the corresponding coordinate of vector by the length of the vector. The coordinates of the unit vector is equal to its direction cosines. Property of direction cosines. The sum of the squares of the direction cosines is equal to one.
