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blondinia [14]
3 years ago
5

11. In June, you start a holiday savings account

Mathematics
1 answer:
zaharov [31]3 years ago
5 0

How much money will you have saved by

the end of December will be $54

Since you increase each monthly deposit by $4

Hence, June to December will give us 6 months

Now let determine How much money will you have saved by the end of December

December ending Amount saved= $30 +($4 × 6 months)

December ending Amount saved= $30 +$24

December ending Amount saved= $54

Inconclusion How much money will you have saved by the end of December will be $54

Learn more here:

brainly.com/question/24598420

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7 0
3 years ago
Read 2 more answers
Given the data
Alexus [3.1K]

Answer:

(a) Mean = 1.6244      (b) Median = 1.65

(c) Mode = 1.35          (d) Range = 1.39

(e) Standard deviation = 0.3325

(f) Variance = 0.1106

(g) Coefficient of variation = 20.47%.

Step-by-step explanation:

The mean (<em>μ</em>) of a data set is the average value of the data set. The formula to compute mean is:

\mu=\frac{1}{n}\sum X_{i}

The median (<em>m</em>) is a quantity in statistics that points out where the mid-value of a data set is. In case of, odd number of data-values, the median is given by,

Median=(\frac{n+1}{2})^{th}\ obs.

The mode (<em>M</em>) of a data set is the value that appears most often.

The range of a data-set is the difference between the maximum and minimum values in the data-set.

Range=Max.-Min.

The standard deviation of a data set is a numerical value that represents the amount of variation between the observed values.

SD=\sqrt{\frac{1}{n-1}\sum (X_{i}-\mu)^{2}}

The variance is the square of the standard deviation.

Var=\frac{1}{n-1}\sum (X_{i}-\mu)^{2}

The coefficient of variation (<em>CV</em>) is well defined as the ratio of the standard deviation to the mean. It exhibits the degree of variation in association to the mean of the population.

The formula to compute the coefficient of variation is,  

CV=\frac{\sigma}{\mu}\times 100\%

Consider the data set provided.

(a)

Compute the mean as follows:

\mu=\frac{1}{n}\sum X_{i}=\frac{1}{25}\times 40.61=1.6244

Thus, the mean of the data is 1.6244.

(b)

Compute the median as follows:

Arrange the data in ascending order as follows:

0.9 , 1.05 , 1.27 , 1.3 , 1.32 , 1.35 , 1.35 , 1.42 , 1.47 , 1.47 , 1.55 , 1.63 , 1.65 ,

1.66 , 1.71 , 1.74 , 1.78 , 1.82 , 1.85 , 1.92 , 1.95 , 1.96 , 2.06 , 2.14 , 2.29

Median=(\frac{n+1}{2})^{th}\ obs.=(\frac{25+1}{2})^{th}\ obs.=13^{th}\ obs.=1.65

Thus, the median of the data set is 1.65.

(c)

Compute the mode as follows:

Consider the data arranged in ascending order above.

0.9 , 1.05 , 1.27 , 1.3 , 1.32 , 1.35 , 1.35 , 1.42 , 1.47 , 1.47 , 1.55 , 1.63 , 1.65 ,

1.66 , 1.71 , 1.74 , 1.78 , 1.82 , 1.85 , 1.92 , 1.95 , 1.96 , 2.06 , 2.14 , 2.29

The value 1.35 repeats twice and none of the other values repeat themselves.

Thus, the mode of the data set is 1.35.

(d)

Compute the range as follows:

Range=Max.-Min.\\=2.29-0.90\\=1.39

Thus, the range of the data set is 1.39.

(e)

Compute the standard deviation as follows:

SD=\sqrt{\frac{1}{n-1}\sum (X_{i}-\mu)^{2}}=\sqrt{\frac{1}{25-1}\sum (X_{i}-1.6244)^{2}}=0.3325

Thus, the standard deviation is 0.3325.

(f)

Compute the variance as follows:

Var=(SD)^{2}=(0.3325)^{2}=0.1106

Thus, the variance is 0.1106.

(g)

Compute the coefficient of variation as follows:

CV=\frac{\sigma}{\mu}\times 100\%=\frac{0.3325}{1.6244}\times 100\%=20.47\%

Thus, the coefficient of variation is 20.47%.

The histogram is attached below.

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Step-by-step explanation:

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3 years ago
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