The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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Answer:
27
Step-by-step explanation:
If the ratio is 1:3 multiply that by 9:9 so you effectively get 9:9x3 = 9:27. Or, you can say to yourself if B (3) is 3 times greater than A (1) then B is 3 times greater than 9. So 9x3 = 27
Step-by-step explanation:
We have AB = 7, Angle ABC = 70°
and Angle ACB = 90°.
Angle BAC = 180° - 70° - 90° = 20°
(Sum of angles in a triangle = 180°)
Using Trignometry,
AC = 7sin70° = 6.58.
BC = 7cos70° = 2.39.
Answer:
The answer to your question is a) (f°g)(x) = 4x² + 2
b) (f + g)(x) = 4x² + x + 2
c) (f - g)(-3) = -37
Step-by-step explanation:
Data
f(x) = x + 2
g(x) = 4x²
a) Calculate (f°g)(x)
Just sum the function
(f°g)(x) = (4x²) + 2
-Simplification
(f°g)(x) = 4x² + 2
b) (f + g)(x)
(f + g)(x) = x + 2 + 4x²
-Simplification
(f + g)(x) = 4x² + x + 2
c) (f - g)(-3)
-Calculate (f - g)(x)
(f - g)(x) = x + 2 - 4x²
-Simplify
(f - g)(x) = -4x² + x + 2
-Evaluate in (-3)
(f - g)(-3) = -(4)(-3)² + (-3) + 2
-Simplification
(f - g)(-3) = -4(9) - 3 + 2
-Result
(f - g)(-3) = -36 - 3 + 2
(f - g)(-3) = -37