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Vedmedyk [2.9K]
3 years ago
5

!!!!!!! I NEED THE WORK PLS ILL GIVE BRAINLIST!!!

Mathematics
1 answer:
dexar [7]3 years ago
3 0

Answer:

1. 4 and 4sqrt2

2. 6sqrt2 and 6sqrt2

3. 5 and 5sqrt2

4. 5sqrt2 and 5sqrt2

5. 6 and 6

6. 8 and 8sqrt2

7. sqrt3 and sqrt6

8. sqrt2 and sqrt4

Step-by-step explanation:

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An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

8 0
3 years ago
Which Trigonometric functions have a domain of (-1,1)
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

[−1,1] and [0, \pi]

hope this helped :)

8 0
3 years ago
Read 2 more answers
An observer on a cliff 1000 yards above sea level sights two ships due east. The angles of depression from the observers perspec
Anika [276]

Answer:

480.53 yards

Step-by-step explanation:

cos(35) = 1000/hypotenuse1    - multiply by h (hypotenuse)

(h1)cos(35) = 1000        - divide by cos(35)

h1 = 1000 / cos(35)

h1 = 1220.7746

Same thing with the angle of depression of 54 degrees.

h2 = 1000 / cos(54)

h2 = 1701.3016

h2 - h1 = 480.53

3 0
3 years ago
If ABCD is an A4 sheet and BCPO is the square, prove that △OCD is an isosceles triangle. And find the angles marked as 1 to 8 wi
Dmitry [639]

Answer:

The diagram for the question is missing, but I found an appropriate diagram fo the question:

Proof:

since OC = CD = 297mm Therefore, Δ OCD is an isoscless triangle

∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

∠DOP = 22.5°

∠PDO = 67.5°

∠ADO = 22.5°

∠AOD = 67.5°

Step-by-step explanation:

Given:

AB = CD = 297 mm

AD = BC = 210 mm

BCPO is a square

∴ BC = OP = CP = OB = 210mm

Solving for OC

OCB is a right anlgled triangle

using Pythagoras theorem

(Hypotenuse)² = Sum of square of the other two sides

(OC)² = (OB)² + (BC)²

(OC)² = 210² + 210²

(OC)² = 44100 + 44100

OC = √(88200

OC = 296.98 = 297

OC = 297mm

An isosceless tringle is a triangle that has two equal sides

Therefore for △OCD

CD = OC = 297mm; Hence, △OCD is an isosceless triangle.

The marked angles are not given in the diagram, but I am assuming it is all the angles other than the 90° angles

Since BC = OB = 210mm

∠BCO = ∠BOC

since sum of angles in a triangle = 180°

∠BCO + ∠BOC + 90 = 180

(∠BCO + ∠BOC) = 180 - 90

(∠BCO + ∠BOC) = 90°

since ∠BCO = ∠BOC

∴  ∠BCO = ∠BOC = 90/2 = 45

∴ ∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

For ΔOPD

Tan\ \theta = \frac{opposite}{adjacent}\\ Tan\ (\angle DOP) = \frac{87}{210} \\(\angle DOP) = Tan^-1(0.414)\\(\angle DOP) = 22.5 ^{\circ}

Note that DP = 297 - 210 = 87mm

∠PDO + ∠DOP + 90 = 180

∠PDO + 22.5 + 90 = 180

∠PDO = 180 - 90 - 22.5

∠PDO = 67.5°

∠ADO = 22.5° (alternate to ∠DOP)

∠AOD = 67.5° (Alternate to ∠PDO)

3 0
3 years ago
Please help me!
Temka [501]
7. Answer is D! 1 to the 3rd power, 1^3, or 1 cubed as you'll hear it, is 1 because when something is cubed that means it's times itself 3 times. (EX: 4^3 = 4x4x4) 2 cubed is 8. 3 cubed is 27. 4 cubed is 64 and 5 cubed is 125!

8. Answer is C! A is gaining speed and B is the capped speed, meaning it can't get any higher, and C is the loss of speed.
7 0
3 years ago
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