Prepare grouped frequency distribution table
1 answer:
The frequency distribution gives a tabulated representation of the frequency of data values within defined intervals.
Given the scores :
8, 47, 22, 31, 17, 1,38 ,26 ,3 ,34,29,11,27,7,15,24,38,31,21,35,42,42,24,45,23,21,27,29,49,25,48,21,15,18,27,19,45,14,34,37,34
Using a class interval value of 10 :
Class Interval _____ Frequency
0 - 10 ____________ 4
11 - 20 ____________7
21 - 30____________14
31 - 40 ____________9
41 - 50 ____________7
- Histogram of the distribution is attached below.
Therefore, the histogram gives a graphical representation of the frequency distribution table.
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the height of the tree is 23 feet .
<u>Step-by-step explanation:</u>
Here we have , Tony is 5.75 feet tall. Late one afternoon, his shadow was 8 feet long. At the same time, the shadow of a nearby tree was 32 feet long. We need to find Find the height of the tree. Let's find out:
According to question , Tony is 5.75 feet tall. Late one afternoon, his shadow was 8 feet long . Let the angle made between Tony height and his shadow be x . Now , At the same time, the shadow of a nearby tree was 32 feet long. Since the tree is nearby so tree will subtend equal angle of x. Let height of tree be y , So
⇒
But , From tony scenario
⇒
Equating both we get :
⇒
⇒
⇒
Therefore , the height of the tree is 23 feet .
Base of a cube is a square, and in the given figure it's stated that the measure of each side is " x " ft
Therefore it's Area is equal to : -
Now, since it's Area is given as 1/4 ft², let's equate the Areas to find the measure of each side ~
that is ~
It's time to find the volume of cube that is ~
So, let's plug the value of side length (1/2 ft)
Volume is equal to ~
Hence, the required 1/8 or 0.125 ft³
I hope it helped ~