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sdas [7]
4 years ago
5

The speed limit posted on a local highway is 75 mph. Is the average speed on that stretch of highway significantly more than 75m

ph? Forty vehicle’s speeds were recorded by speed detection devices. What would be the correct alternative hypothesis?
Mathematics
1 answer:
defon4 years ago
7 0

Answer: H_a: \mu >75

Step-by-step explanation:

Alternative hypothesis (H_a): It is a statement which always indicates that there is a significant difference between the groups being tested.

It always contains by < , > or ≠ sign .

Given claim  : Is the average speed on that stretch of highway significantly more than 75mph?

Here objective is whether  the average speed on that stretch of highway significantly more than 75mph.

Let \mu be the population mean speed on that stretch of highway significantly more than 75mph.

Then, H_a: \mu >75

Hence , the correct alternative hypothesis would be :  H_a: \mu >75

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Mr. Richards saves $4,639. Then, he uses one fourth of his savings to take flying lessons. How much money does Mr. Richards spen
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Answer:

$1159.75

Step-by-step explanation:

4,639 * 1/4 = 1159.75

4 0
3 years ago
What is the area in square units of the rectangle
Vsevolod [243]
\bf \textit{area of a rectangle}\\\\&#10;A=length\cdot width\qquad \qquad A=\cfrac{3}{7}\cdot \cfrac{2}{9}\implies A=\cfrac{6}{63}\implies A=\cfrac{2}{21}
8 0
4 years ago
Sam invests $6000 in two different accounts. The first account paid 12 %, the second account paid 7 % in interest. At the end of
Lunna [17]

Answer:

The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

Step-by-step explanation:

Let x be the amount in the account at 12% interest

So, 6000-x is the amount in the second account at 7% interest

SI = \frac{P \times T \times R}{100}

First account:SI=\frac{x \times 1 \times 12}{100}

Second account : SI =\frac{(6000-x) \times 1 \times 7}{100}

We are given that At the end of the first year he had earned $590 in interest.

So, \frac{x \times 1 \times 12}{100}+\frac{(6000-x) \times 1 \times 7}{100}=590\\x=3400

So,the amount in the account at 12% interest is $3400

The amount in the second account at 7% interest =6000-x=6000-3400=2600

Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

8 0
4 years ago
Find 17.3% of 286.1. Round to the nearest thousandth.
stealth61 [152]

49 would be the answer I hope it helps

3 0
3 years ago
Read 2 more answers
For the parent function y=√x what effect does a value of k = -3 have on the graph?
luda_lava [24]

Answer:

Vertical shift of 3 units down ⇒ last answer

Step-by-step explanation:

* Lets revise the translation of a function

- If the function f(x) translated horizontally to the right  

 by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  

 by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up  

 by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down  

 by k units, then the new function g(x) = f(x) – k

* Lets solve the problem

∵ The parent function y = √x

∵ There is a translation by k = -3

- From the rules above k is for the vertical translation

∵ k = -3

- That means the parent function translated 3 units down

∴ The value of k = -3 makes the graph of the parent function translated

   3 units down

- For more understand look to the attached graph

# y = √x ⇒ the red graph

# y = √x - 3 ⇒ the blue graph

4 0
3 years ago
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