4. For the three part question that follows, provide your answer to each question in the given workspace. Be sure to clearly lab
el each part of your response as part
A, Part B, and Part C.
Part A: Is there a restriction on the domain for the function root over x^2 - 8= y+1 ? Why, or why not?
Part B: State the domain for the function root over x^2 - 8= y+1. Support your answer by showing your work.
Part C: Explain, in your own words, how
identify restrictions on a domain for any given equation.
A, Part B, and Part C.
Part A: Is there a restriction on the domain for the function root over x^2 - 8= y+1 ? Why, or why not?
Part B: State the domain for the function root over x^2 - 8= y+1. Support your answer by showing your work.
Part C: Explain, in your own words, how
identify restrictions on a domain for any given equation.
1 answer:
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Answer: Length = 70 feet
Concept:
Here, we need to know how to find the perimeter of a rectangle.
Perimeter (rectangle) = 2 (l + w)
l = length
w = width
Solve:
<u>Given information</u>
l = l
w = 51 feet
P = 242 feet
<u>Given expression</u>
P = 2 (l + w)
<u>Substitute values into the expression</u>
242 = 2 (l + 51)
<u>Divide 2 on both sides</u>
242 / 2 = 2 (l + 51) / 2
121 = l + 51
<u>Subtract 51 on both sides</u>
121 - 51 = l + 51 - 51
Hope this helps!! :)
Please let me know if you have any questions
See the picture attached with letters to better understand the problem
in the right triangle ABD
applying the Pythagoras theorem
8²=AD²+(x+4)²-----> AD²=64-(x+4)²------> equation 1
in the right triangle ADC
applying the Pythagoras theorem
12²=AD²+(2x+1)²-----> AD²=144-(2x+1)²------> equation 2
equate equation 1 and equation 2
64-(x+4)²=144-(2x+1)²-------> 64-[x²+8x+16]=144-[4x²+4x+1]
64-x²-8x-16=144-4x²-4x-1
4x²-x²-8x+4x=144-1-64+16
3x²-4x=95
3x²-4x-95=0
using a graph tool----> to resolve the second order equation
see the attached figure N 2
the solution is
x=6.33
the answer is
x=6.33 units
in the right triangle ABD
applying the Pythagoras theorem
8²=AD²+(x+4)²-----> AD²=64-(x+4)²------> equation 1
in the right triangle ADC
applying the Pythagoras theorem
12²=AD²+(2x+1)²-----> AD²=144-(2x+1)²------> equation 2
equate equation 1 and equation 2
64-(x+4)²=144-(2x+1)²-------> 64-[x²+8x+16]=144-[4x²+4x+1]
64-x²-8x-16=144-4x²-4x-1
4x²-x²-8x+4x=144-1-64+16
3x²-4x=95
3x²-4x-95=0
using a graph tool----> to resolve the second order equation
see the attached figure N 2
the solution is
x=6.33
the answer is
x=6.33 units