All categories

3 years ago

How do i find the volume of L-Blocks?

1 answer:

7 0

So the question is how to find the volume of a L-block geometrical body. To do that we need to turn an L-block into something we know how to calculate the volume. in the case of an L-block we can use two rectangles because we can calculate it's volume easily, as V=a*b*c and simply sum the two volumes.

You might be interested in

If 1 box cost rs 45 find the cost of 9 boxes

jarptica [38.1K]

Answer:

9 boxes cost Rs 405

Step-by-step explanation:

1 box costs 45.

so, how much are 2 boxes ? what do you think ?

right, twice as much : 2 × 45 = 90

how much are 3 boxes ?

now it is three times the cost of 1 box : 3 × 45 = 135

do you see the pattern ?

it is really simple.

that is also the origin why we describe a multiplication by "times". we take a single item so and so many times.

when you see something like this, you know, they are talking about multiplication.

so, here we want to know how much 9 boxes cost.

therefore,

9 × 45 = 405

is the answer.

6 0

2 years ago

Find the zeros of f(x) = x^2+5x-6. A. {-2,3} B. {-6,1} c. {-2,-3} D. {-6,-1}

Arisa [49]

Answer:

x^2+5x-6

a = 1 b = 5 and c = -6

Using the quadratic formula:

x = [-5 +- sq root (25 -4 * 1 *-6) ] / 2 * 1

x = [-5 +- sq root (49)] / 2

x = [-5 +- 7] / 2

x1 = 1

x2 = -6

Step-by-step explanation:

7 0

3 years ago

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago

Probability of getting same number when rolling two dice

Soloha48 [4]

6 of them are double 1,1 2,2 3,3 4,4 5,5 6,6
P(doubles)=6/36=1/6

5 0

3 years ago

There are 75 envelopes in a package. How many envelopes are there in 7 packages?

r-ruslan [8.4K]

The question is asking us to calculate how many envelopes are there in 7 packages if there are 75 in a package. For example: in 1 package there are 75 envelopes. In 2 packages there are 7 * 2 = 150 envelopes. In general, formula is : 75 * n, where n is the number of packages. Therefore, we will multiply 75 by 7. 75 * 7 = 525. Answer: B ) 525 envelopes.

8 0

3 years ago