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2 years ago

7

A quadratic and an exponential function were fitted to a data set. Their residual plots

1 answer:

taurus [48]2 years ago

8 0

Answer:

The Exponential function provides a better fit of the data.

Step-by-step explanation:

The closer the data points come to forming a straight line when plotted, the higher the correlation between the two variables, or the stronger the relationship. In comparing the scatterplots of Quadratic and Exponential functions, it is obvious that the points are clustered closer together in the Exponential function, while the data points on the Quadratic Function are more spread out.

Therefore, the Exponential function provides a better fit of the data set.

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Please help or else your not getting a signed autograph by Shrek!

Vinil7 [7]

Answer:

HERE SHREK TV

Step-by-step explanation:

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2 years ago

Solve the problem. Make sure your answer is in simplest form and improper fractions are expressed as mixed numbers.

pogonyaev

22/5=4 and 2/5

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2 years ago

Read 2 more answers

Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as the sum, difference

kicyunya [14]

Answer:

$\\ ln(x^2) - ln(x^2 + 1)$ .

For values of x>0, it can be rewritten as $\\ 2ln(x) - ln(x^2 + 1).$

Step-by-step explanation:

For the expression:

$\\ ln(\frac{x^2}{x^2 + 1})$

We can apply this logarithmical property: $\\ ln(\frac{x}{y}) = ln(x) - ln(y).$

Then,

$\\ \frac{x^2}{x^2 + 1} = ln(x^2) - ln(x^2 + 1).$

If we assume values of <em>x </em>> 0 (non negative values for x), then the expression could be rewritten as follows:

$\\ \frac{x^2}{x^2 + 1} = ln(x^2) - ln(x^2 + 1) = 2 ln(x) - ln(x^2 + 1)$ , since $\\ ln(x^{n}) = n*ln(x).$

We have to remember that <em>domain</em> (all possible values x) for logarithmic function is for all x > 0, or mathematically expressed as:

Domain: $\\ {x | x \in R, x > 0}$

8 0

2 years ago

Express $7.45 for 2.5 pounds of round steak as a unit rate.

Digiron [165]

unit rate: $7.45/2.5 lbs of steak

--------------------------------

reduced:

7.45 dollars /2.5 pounds

GCF=0.5

7.45/0.5=14.9$

2.5/0.5=5

unit rate:

$14.9/5 pounds

6 0

3 years ago

Answer questions (a – d) for the following three data sets. A = {3, 5, 7, 9, 11, 12, 12} B = {1, 2, 2, 5, 5, 9, 13} C = {2, 5, 8

jekas [21]

Answer:#carry on learning

mark me as brainliest

a.8.4

b.5.4

c.9.4

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2 years ago