I believe it would be x=2i
:)
The equation for which square method is possible is x²-8=1
Step-by-step explanation:
For checking which of the equation satisfies the complete square condition, we proceed by checking each of the available options
1). x²+20x=52
Rewriting it as x²+20x-52
This binomial expression is not a perfect square since the product of the coefficient of x²(i.e. 1) and independent constant (i.e. 52) is not a perfect square.
2). 5x² + 3x = 9
This equation can be rearranged as 5x²+3x-9=0
This binomial expression is not a perfect square since the product of the coefficient of x²(i.e. 5) and independent constant(i.e. 9) is not a perfect square.
3.) x² −8=1
This equation can be rearranged as x²=9
Hence x= ±3
This binomial expression is a perfect square and can be done by the square method.
4). 3x² −x+17=0
This binomial expression is not a perfect square since the product of the coefficient of x²(i.e. 3) and independent constant(i.e. 17) is not a perfect square.
Answer:
A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12
Step-by-step explanation:
In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.
3 = -b/2(1)
3 = -b/2
6 = -b
b = -6
Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.
Answer:
x
^2/
6
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