Answer:
Journal Entries
Date Accounts Titles Debit Credit
Nov 1 Warranty expense $3,120
($52,000 * 6%)
Estimated warranty payable $3,120
Nov 20 Estimated warranty payable $1,600
Cash $1,600
Dec 31 Vacation benefit expense $6,000
Vacation benefit payable $6,000
Dec 31 Employee bonus expense $1
,515
Employee bonus payable $1,515
<u>Working</u>
Bonus = 3% * (Net income-Bonus)
Let bonus= x
x = 3% * (52,000 - (1+x))
x = 0.03 * (52,000- (1+x))
x = 1560 - 1.03
1.03x = 1560
x = $1,560 / 1.03
x = $1,514.5631
Bonus= $1,515
The correct answer would be : Birthrate
I hope that this helps you !
The answer to this question
would be:
<span>The
aspect of organizational culture this represent is<span>
<u>“Material Artifacts and Symbols”.</u></span></span>
<u>
</u>
<span>
Placing the
parking spot of the employee of the month nearest the front door symbolizes the
importance of that and the kind of perks he is receiving.</span>
Answer:
Market penetration
Explanation:
Market penetration Is when the initial price of a new good or service is set really low. This is usually done to encourage consumers to demand for the product and to reduce the demand for competitors goods or services.
Market penetration is ususally done to gain market share and attract customers to a new product. After a period of time , prices would rise to normal levels.
Nintendo price was lower than Sega's price, it is expected that consumers would demand more of Nintendo and less of Sega games.
I hope my answer helps you.
Answer:
x1 + x2 + x3 + x4 + x5 + x6 + x7
Explanation:
Formulating the problem as an LP
Attached below is an AOA diagram and the completion time of each task is indicated in the diagram, The diagram was based on the conditions given for the completion of each task accordingly.
To complete the project as early as possible we will have assume
x1, x2, x3, x4, x5, x6, and x7 to be the times taken to complete each node
hence the earliest time taken to complete the project
= x1 + x2 + x3 + x4 + x5 + x6 + x7
when : x2 - x1 ≥ 3
x3 - x2 ≥ 2
x4 - x2 ≥ 2
x5 - x3 ≥ 3
x6 - x3 ≥ 3
x7 - x5 ≥ 1
x7 - x6 ≥ 1
also : x1, ............ , x7 ≥ 0
