(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.
Answer:
The answer is 1 13/27.
Step-by-step explanation:
First, convert any mixed numbers to fractions --
the initial equations then reads as 5/3 x 8/9.
Then, applying the fractions formula for multiplication --
5 x 8 / 3 x 9
40/27
Simplifying the above --
1 13/27
Answer:
A, B, E area ll less than 0
Step-by-step explanation:
They are all negative numbers.
I think its B , because if you connect the TWO dots forming a triangle its 3 up and 4 to the right making 3/4 as the slope and the Y intercept is 1 so y=3/4x +1
Answer:
Step-by-step explanation:
suface area of base=1/2×9×7.8=9×3.9=35.1 yd²
lateral surface area=3×1/2×9×10=135 yd²
total surface area=135+35.1=170.1 yd²
i assumed it is an equilateral triangular base.
as √(7.8²+4.5²)=9.0049≈9
