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Rom4ik [11]
3 years ago
9

Show all work and provide necessary descriptions

Mathematics
1 answer:
masya89 [10]3 years ago
5 0

Let

P=(P_x,P_y),\quad Q=(Q_x,Q_y)

If M is the midpoint, the x and y coordinates of M are the average of the x and y coordinates of P and Q:

M=\left(\dfrac{P_x+Q_x}{2},\ \dfrac{P_y+Q_y}{2}\right)

We can solve this expression for the coordinates of Q:

M_x = \dfrac{P_x+Q_x}{2} \implies Q_x = 2M_x-P_x

M_y = \dfrac{P_y+Q_y}{2} \implies Q_y = 2M_y-P_y

Plug in the values for the coordinates of M and P to get

Q_x = 2M_x-P_x = 2\cdot 5-11 = 10-11=-1

Q_y = 2M_y-P_y = 2\cdot (-2) - (-10) = -4+10=6

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<u>Step 1:</u> Divide 'y' into 2 parts, 'a' and 'b'. 'a' would be the lower leg of the 45°-45°-90° triangle, while 'b' is the lower leg of the 30°-60°-90° triangle.<em>
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</em><u />     y = a + b
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And there you have it! <em>Hope this helps.</em>
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