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Rom4ik [11]
3 years ago
9

Show all work and provide necessary descriptions

Mathematics
1 answer:
masya89 [10]3 years ago
5 0

Let

P=(P_x,P_y),\quad Q=(Q_x,Q_y)

If M is the midpoint, the x and y coordinates of M are the average of the x and y coordinates of P and Q:

M=\left(\dfrac{P_x+Q_x}{2},\ \dfrac{P_y+Q_y}{2}\right)

We can solve this expression for the coordinates of Q:

M_x = \dfrac{P_x+Q_x}{2} \implies Q_x = 2M_x-P_x

M_y = \dfrac{P_y+Q_y}{2} \implies Q_y = 2M_y-P_y

Plug in the values for the coordinates of M and P to get

Q_x = 2M_x-P_x = 2\cdot 5-11 = 10-11=-1

Q_y = 2M_y-P_y = 2\cdot (-2) - (-10) = -4+10=6

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Step-by-step explanation:

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Please help with this question. Thank you
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5 0
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A gumball machine has contains orange,yellow,and purple gum balls is 3 over 4.the probability of getting a yellow gum ball is 1
stich3 [128]
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6 0
3 years ago
Rob peeled 125 oranges in 5 hours. At that rate, how many oranges<br> would he peel in 12 minutes?
marin [14]

Answer:

\boxed {\tt 5 \ oranges}

Step-by-step explanation:

Let's set up a proportion.

\frac{oranges}{minutes} =\frac{oranges}{minutes}

He can peel 125 oranges in 5 hours. First, let's find the minutes in 5 hours.

There are 60 minutes in 1 hour, so multiply 60 and 5 (60*5=300). There are 300 minutes in 5 hours.

\frac{125 \ oranges}{300 \ minutes}=\frac{oranges}{minutes}

We don't know how many oranges he can peel in 12 minutes. So we say he can peel x oranges in 12 minutes.

\frac{125 \ oranges}{300 \ minutes}=\frac{x \ oranges}{12 \ minutes}

\frac{125 \ }{300 \ }=\frac{x \ }{12 }

Solve for x by isolating it. x is being divided by 12. The inverse of division is multiplication. Multiply both sides of the proportion by 12.

12*\frac{125 \ }{300 \ }=\frac{x \ }{12 \ }*12

12*\frac{125 \ }{300 \ }=x

12*0.416666667=x

5=x

Rob can peel 5 oranges in 12 minutes.

6 0
4 years ago
Read 2 more answers
A recipe for lemon bars called for 9" X 13" pan. How many 1" X 1" bars can be cut? How many 2" X 2" bars can be cut? How much is
gregori [183]

The number of bars which can be cut for the 1" X 1" and 2" X 2" square bars are; 117 and 29 units respectively.

<h3>How many bars can be cut from the pan in each case?</h3>

The total area of the given pan can be evaluated as follows;

Area = length × width

= 9 × 13

= 117 square units.

Hence, the number of 1" X 1" bars can be cut which can be cut from the pan;

= 117/(1×1)

= 117 1" X 1" bars.

For the 2" X 2" square bars, we have;

= 117/(2×2);

29 remainder 1 square unit.

Ultimately, one square unit of the pan is wasted for the 2" X 2" square bars.

Read more on area;

brainly.com/question/8294080

#SPJ1

8 0
2 years ago
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