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2 years ago

What is meant by the term outlier? What should you do with an outlier?

Mathematics

1 answer:

saul85 [17]2 years ago

7 0

Outliers are data that are in a very far distance from other values in a set of data

Once an outlier is detected in a set of data, we can do the following to them:

Discard the outlier
Change the value of the outlier with another value within close range
Consider the distribution given

We may have a set of data where some of the values are far in distance from the majority of the data. The set of such data are known as an outlier.

For example, give the set of data;

2, 4, 7, 45, 8

45 can be considered as an outlier since the distance of data to all other data is large.

Once an outlier is detected in a set of data, we can do the following to them:

Discard the outlier
Change the value of the outlier with another value within close range
Consider the distribution given

Learn more here: brainly.com/question/23258173

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ashley is baking a cake shaped as a right triangle. Two of the angles are measurement of 5x and 10x. What is the value of x?

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the

AVprozaik [17]

Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: