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salantis [7]
3 years ago
10

Evaluate -x + 4y when x =

Mathematics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

8

Step-by-step explanation:

-4/5+4(1)/3 = -4/5 + 4/3

L.C.M = 15

then -12+20/15 = 8/15

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Answer:10x

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Answer is the third one or C. Can I have brainliest?! Please?!
8 0
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Select the correct answer.
arsen [322]

Answer:

D is right

Step-by-step explanation:

5 0
3 years ago
What is 3/m-2 = 7/m+2
kirill115 [55]

Answer:

3/m-2=7/m+2

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3m+6=7m-14

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6 0
3 years ago
According to a survey by the Administrative Management Society, one-half of U.S. companies give employees 4 weeks of vacation af
andreyandreev [35.5K]

Answer:

a

P(2\leq X\leq 5)=0.875

b

P(X

Step-by-step explanation:

Let the random X variable representing the 6 companies that give 4 weeks of vacation after 15 years of employment:

-let p=0.5 be the probability of vacation. Since the companies are independent, X assumes a binomial random variable:P(X=x)=b(x;6,0.5)\\\\={6 \choose x}(0.5)^x(0.5)^{6-x}\\\\={6 \choose x}(0.5)^6, \ x=0,1,2,3...\ \ \ eqtn1

#Probability that the number of companies that give vacation is anywhere from 2 to 5:

We use equation 1;

P(2\leq X\leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\={6 \choose 2}(0.5)^6+{6 \choose 3}(0.5)^6{6 \choose 4}(0.5)^6+{6 \choose 5}(0.5)^6\\\\=0.0156(15+20+15+6)\\\\=0.875

Hence the probability that between 2 and 5 companies give vacation is 0.875

b. The probability that fewer than 3 companies give vacation is calculated as:

From equation one we get:

P(X

Hence the probability that less than three companies give vacation is 0.3432

3 0
3 years ago
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