Ms. Cassidy instructed Miguel to change one sign of the graph of y < 2x – 4 so that point (2, 3) can be included in the solution set.
To check which of the given options might Miguel write we check the inequality that holds true for the point (2,3).Substituting x=2 ,y=3 we have:
1) y < 2x – 1
3<2(2)-1
3<3 Not True.
2)y ≤ 2x – 4
3≤ 2(2) -4
3≤ 0 .Not true.
3) y > 2x – 4
3> 2(2)-4
3> 0 True.
4) y < 2x + 4
3<2(2)+4
3<8 True
5) .y < 3.5x – 4
3< 3.5(2)-4
3<3 Not true
6) y < 4x – 4
3<4(2)-4
3<4 True.
Options 3 ,4 ,6 holds true for the point (2,3)
Answer:
dsdsdsdsdsdssdsddddddddd
Step-by-step explanation:
Answer & Step-by-step explanation:
In order to solve this problem, it's important that we look at the tiles and the the signs that are in front of them. The top row of tiles represents our first expression and the bottom row of tiles represents our second equation.
The two large tiles are positive so they are going to be positive in our equation.
(x² ) - (-x² )
The four blue rectangle tiles are also positive, so they are going to be positive in our equation. The two red rectangle tiles are negative, so they are going to be negative in out equation.
(x² + 4x) - (-x² + 2x)
The two red square tiles are negative, so they are going to be negative in our equation. The four blue square tiles are positive, so they are going to be positive in our equation.
(x² + 4x - 2) - (-x² + 2x - 4)
So, your answer is going to be letter choice C.
Answer:
the largest angle of the field is 149⁰
Step-by-step explanation:
Given;
perimeter of the triangular filed, P = 120 m
length of two known sides, a and b = 21 m and 40 m respectively
The length of the third side is calculated as follows;
a + b + c = P
21 m + 40 m + c = 120 m
61 m + c = 120 m
c = 120 m - 61 m
c = 59 m
B
↓ ↓
↓ ↓
↓ ↓
A → → → → → → → → → → → C
Consider ABC as the triangular field;
Angle A is calculated by applying cosine rule;

Angle B is calculated as follows;

Angle C is calculated as follows;

Therefore, the largest angle of the field is 149⁰.