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meriva
3 years ago
5

In a class of 27 students, 7 have a cat and 9 have a dog. There are 5 students who have a cat and a dog. What is the probability

that a student has a dog given that they have a cat?
Mathematics
1 answer:
Lelechka [254]3 years ago
4 0

Answer: 5/7

Step-by-step explanation: 27 and 9 are both irrelevant numbers.

If we see here, it is given that they have a cat. 7 people have a cat! And because those 5 students who have both are listed under both categories, there are 5 students in the 7! Therefore, 5/7 is the desired probability...

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Which fraction is greater than 4/8 a.1/2 b.1/4 c.7/8 d.3/5
Nastasia [14]

Answer:

c and d

Step-by-step explanation:

4/8 = 1/2

a.1/2 =1/2 so it is not greater

b.1/4  <  1/2 = 2/4  so 4/8 is greater

c.7/8   > 4/8  so 7/8 is greater

d.3/5     3/5 = 6/10    1/2 = 5/10

                     3/5 >     4/8

5 0
3 years ago
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3. Barbara and Luke each placed 2 meter sticks end-to-end along the length of a large table. About how long is the table?
kompoz [17]
I this is the entire question the answer is 78.74 inches or 6 1/2 feet
5 0
4 years ago
The weight of an organ in adult males has a​ bell-shaped distribution with a mean of 350 grams and a standard deviation of 45 gr
Svetach [21]

Answer:

a) About 68% of the data would be between 305 grams to 395 grams

b) About 95% of organs weighs between 260 grams and 440 ​grams

c)About 5% of organs weighs less than 260 grams or more than 440 ​grams

d) About 97% of organs weighs between 215 grams and 440 ​grams

Step-by-step explanation:

The empirical rule formula:

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ

​(a) About 68​% of organs will be between what​ weights?

We would be applying the First rule of the Empirical formula to this.

68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

Mean = 350 grams

Standard deviation = 45 grams

Hence,

350 grams - 45 grams

= 305 grams

350grams + 45grams

= 395 grams

Therefore about 68% of the data would be between 305 grams to 395 grams

​(b) What percentage of organs weighs between 260 grams and 440 ​grams?

Let try the second rule

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

Mean = 350 grams

Standard deviation = 45 grams

μ - 2σ

= 350 - 2(45)

= 350 - 90

= 260

μ + 2σ

= 350 + 2(45)

= 350 + 90

= 440

Therefore, about 95% of organs weighs between 260 grams and 440 ​grams

​(c) What percentage of organs weighs less than 260 grams or more than 440 ​grams? ​

Let try the second rule

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

Mean = 350 grams

Standard deviation = 45 grams

μ + 2σ

= 350 - 2(45)

= 350 - 90

= 260

μ + 2σ

= 350 + 2(45)

= 350 + 90

= 440

Since, about 95% of organs weighs between 260 grams and 440 ​grams, the percentage of organs weighs less than 260 grams or more than 440 ​grams is calculated as:

100% - 95%

= 5%

Therefore, percentage of organs weighs less than 260 grams or more than 440 ​grams is 5%

(d) What percentage of organs weighs between 215 grams and 440 ​grams?

For 215 grams, we apply the 3rd rule to confirm

= 3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ

Mean = 350 grams

Standard deviation = 45 grams

μ - 3σ

= 350 - 3(45)

= 350 - 135

= 215.

Hence, 99% of the organs weigh 215 grams

For 440, from the solve questions above, we know the second rule applies.

Hence,

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

Mean = 350 grams

Standard deviation = 45 grams

μ + 2σ

= 350 + 2(45)

= 350 + 90

= 440

Hence,

99% + 95%/ 2

= 194% / 2

= 97%

Therefore, about 97% of organs weighs between 215 grams and 440 ​grams

4 0
3 years ago
Stewart School has 178 computers. Grade 3 has 58 computers and flgrade 4 has 57 computers. What equations can be used to find ho
Ilya [14]

Answer: x=58+57=115

y=178-115=63


Step-by-step explanation:

Let x be the number of computers Grade 3 and grade 4 has and y be the numbers of computers the rest of school has.

Then, x= Grade 3 computers +Grade 4 computers.

\Rightarrow\ x=58+57=115

And y = Total computers - x

\Rightarrow\ y=178-115=63

Therefore, The  equations can be used to find how many computers the rest of the school has.

x=58+57=115

y=178-115=63



7 0
4 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csin%20%7B%7D%5E%7B2%7D%20%28a%29%20%20%2B%20cos%20%7B%7D%5E%7B2%7D%20%28a%29%20%3D%20" i
ludmilkaskok [199]

Answer:

sin^2a+ cos^2a=1

it is derived from Pythagoras theorem

3 0
4 years ago
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