Answer:
64% = 16/25 = 0.64
12.5% = 1/8 = .125
140% = 1 and 2/5 = 1.4
275% = 2 and 3/4 = 2.75
8%= 2/25 = 0.08
Step-by-step explanation:
i hope this helps if it does please give brainliest
The equation of the line that is perpendicular to 4x - 3y = 10 through the point (-2,4) is ![y-4=\frac{-3}{4}(x+2)](https://tex.z-dn.net/?f=y-4%3D%5Cfrac%7B-3%7D%7B4%7D%28x%2B2%29)
<u>Solution:</u>
Given, line equation is 4x – 3y = 10
We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)
Now, let us find the slope of the given line,
![\text { Slope of a line }=\frac{-\mathrm{x} \text { coefficient }}{\mathrm{y} \text { coefficient }}=\frac{-4}{-3}=\frac{4}{3}](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Slope%20of%20a%20line%20%7D%3D%5Cfrac%7B-%5Cmathrm%7Bx%7D%20%5Ctext%20%7B%20coefficient%20%7D%7D%7B%5Cmathrm%7By%7D%20%5Ctext%20%7B%20coefficient%20%7D%7D%3D%5Cfrac%7B-4%7D%7B-3%7D%3D%5Cfrac%7B4%7D%7B3%7D)
We know that, slope of a line
slope of perpendicular line = -1
![\begin{array}{l}{\text { Then, } \frac{4}{3} \times \text { slope of perpendicular line }=-1} \\\\ {\rightarrow \text { slope of perpendicular line }=-1 \times \frac{3}{4}=-\frac{3}{4}}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7B%20Then%2C%20%7D%20%5Cfrac%7B4%7D%7B3%7D%20%5Ctimes%20%5Ctext%20%7B%20slope%20of%20perpendicular%20line%20%7D%3D-1%7D%20%5C%5C%5C%5C%20%7B%5Crightarrow%20%5Ctext%20%7B%20slope%20of%20perpendicular%20line%20%7D%3D-1%20%5Ctimes%20%5Cfrac%7B3%7D%7B4%7D%3D-%5Cfrac%7B3%7D%7B4%7D%7D%5Cend%7Barray%7D)
Now, slope of our required line =
and it passes through (-2, 4)
<em><u>The point slope form is given as:</u></em>
![\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }} \\\\ {\text { Here in our problem, } m=-\frac{3}{4}, \text { and }\left(x_{1}, y_{1}\right)=(-2,4)} \\\\ {\text { Then, line equation } \rightarrow y-4=-\frac{3}{4}(x-(-2))}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7By-y_%7B1%7D%3Dm%5Cleft%28x-x_%7B1%7D%5Cright%29%20%5Ctext%20%7B%20where%20%7D%20m%20%5Ctext%20%7B%20is%20slope%20and%20%7D%5Cleft%28x_%7B1%7D%2C%20y_%7B1%7D%5Cright%29%20%5Ctext%20%7B%20is%20point%20on%20the%20line.%20%7D%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7B%20Here%20in%20our%20problem%2C%20%7D%20m%3D-%5Cfrac%7B3%7D%7B4%7D%2C%20%5Ctext%20%7B%20and%20%7D%5Cleft%28x_%7B1%7D%2C%20y_%7B1%7D%5Cright%29%3D%28-2%2C4%29%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7B%20Then%2C%20line%20equation%20%7D%20%5Crightarrow%20y-4%3D-%5Cfrac%7B3%7D%7B4%7D%28x-%28-2%29%29%7D%5Cend%7Barray%7D)
![y-4=\frac{-3}{4}(x+2)](https://tex.z-dn.net/?f=y-4%3D%5Cfrac%7B-3%7D%7B4%7D%28x%2B2%29)
Hence the equation of line is found out
Answer:
Therefore, Δx=5/n, when have n intervals.
Step-by-step explanation:
From exercise we have interval [0,5]. So the length of the given interval is 5-0=5. Since all intervals [x0,x1],[x1,x2],…,[xn−1,xn] are equal in width.
We know that their width is Δx. We conclude that width of each subinterval Δx in terms of the number of subintervals n is equal 5/n.
Therefore, Δx=5/n, when have n intervals.