Here,
y=mx+c
the slope of the line 6x+4y= -16 is -20.
if the two lines are perpendicular, the slope of 1st line * slope of second line=-1
the slope of the 2nd line is -1/2
y-y1=m(x-x1)
y-13=-1/2(x- -18)
when you solve, you get the equation of the line as 2y+x=50
In basic geometry, if two geometry objects intersect at right angles (90 degrees or π / 2 radians), they are vertical.
If two lines intersect at right angles, the line is perpendicular to another line. Explicitly (1) if two lines intersect, the first line is perpendicular to the second line. (2) At the intersection, the straight line angle on one side of the first line is cut by the second line into two congruent angles. Verticality can be shown as symmetric. That is, if the first line is perpendicular to the second line, then the second line is also perpendicular to the first line. Therefore, two straight lines can be said to be perpendicular (to each other) without specifying the order.
Learn more about Perpendicular here: brainly.com/question/7098341
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Scene two because he has more than half of the lines
9514 1404 393
Answer:
5. x = 160; y = 20
6. h = 125°; g = i = 55°
Step-by-step explanation:
Vertical angles are found on opposite sides of a point where lines cross. Each angle is formed from rays opposite those of the other angle. Vertical angles are congruent.
5. x° and 160° are vertical angles: x° = 160°
y° and 20° are vertical angles: y° = 20°
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6. h° and 125° are vertical angles: h° = 125°
The angles g° and 125° form a "linear pair" so total 180°.
g° = 180° -125° = 55°
g° and i° are vertical angles: g° = i° = 55°
If you can find one leg of a triangle to be congruent to a leg on the other triangle, then you can use the HL (hypotenuse leg) theorem. If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and a leg of another right triangle, then the triangles are congruent.
120 - 3/4y=60
lowest common multiple=4y
480y-3=240y
480y-240y=3
240y=3
y=3/240
y=1/80
Answer: y=1/80
