500 people took the survey.
12 out of 15 people is 80% of the population. 12/15 = 0.80
Thus, 80% of the population prefers eating in the restaurant.
If 400 represents the people who prefers eating in the restaurant; then, 400 is the 80% of the population. To get the total population or 100%, we must divide 400 by 0.80 or 80%
400 / 0.80 = 500 people.
Out of the 500 people, 400 selected eating in the restaurant while the remaining 20% of the population or 100 people selected cooking at home.
I think the Answer is 76 in^2
Hope this helps
The answer is -7
The arrows both point toward the left side, and sine there are seven spaces the arrows are going through, you subtract 7 spaces and get -7
Hope that helps.
Step-by-step explanation:
You are just replacing the 'n' with the number in the 'n box'.
So if this is the formula:
![b(n) = 4 - (n \div 3)](https://tex.z-dn.net/?f=b%28n%29%20%3D%204%20-%20%28n%20%5Cdiv%203%29)
then:
B(-3)= 4-(-3/3)
B(-3)= 4-( -1)
B(-3)= 4+1
B(-3)= 5
B(0)= 4-(0/3)
B(0)= 4-0
B(0)= 4
B(3)= 4-(3/3)
B(3)= 4-1
B(3)= 3
Answer:
<h3>25%</h3>
Step-by-step explanation:
Total number of student in the school = 152 students
Number of student that have more than one pet = 38
percentage of the students have more than one pet will be expressed as
% of student with more than 1 pet = number of student with more than one pet/total number of student * 100%
% of student with more than 1 pet = 38/152 * 100
% of student with more than 1 pet = 3800/152
% of student with more than 1 pet = 25%
Hence 25% of the students in the school have more than one pet.