Answer:
-98
Step-by-step explanation:
Answer:
The expected value for a student to spend on lunch each day = $5.18
Step-by-step explanation:
Given the data:
Number of students______$ spent
2 students______________$10
1 student________________$8
12 students______________$6
23 students______________$5
8 students_______________$4
4 students_______________$3
Sample size, n = 50.
Let's first find the value on each amount spent with the formula:
Therefore,
For $10:
For $8:
l
For $6:
For $5:
For $4:
For $3:
To find the expected value a student spends on lunch each day, let's add all the values together.
Expected value =
$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24
= $5.18
Therefore, the expected value for a student to spend on lunch each day is $5.18
Answer:
-18.
Step-by-step explanation:
They're both negative numbers being added to each other, so you'd add 6 and 12 (which is 18) and then put a negative sign before the 18. Therefore, your answer is -18.
I hope this helps, have a nice day.
Answer:
a) P=0.2503
b) P=0.2759
c) P=0.3874
d) P=0.2051
Step-by-step explanation:
We have this information:
25% of American households have only dogs (one or more dogs)
15% of American households have only cats (one or more cats)
10% of American households have dogs and cats (one or more of each)
50% of American households do not have any dogs or cats.
The sample is n=10
a) Probability that exactly 3 have only dogs (p=0.25)

b) Probability that exactly 2 has only cats (p=0.15)

c) Probability that exactly 1 has cats and dogs (p=0.1)

d) Probability that exactly 4 has neither cats or dogs (p=0.5)
