Note that there are some duplicate events in the given distribution. I'm guessing you meant to describe the table below:

(imagine there are horizontal lines separating the rows in the table; for whatever reason, the command for making these lines doesn't work on this site)
The covariance is

which follows from



The correlation is

since


because


Next, recall that

where

Then we have, for instance,

so that

and so

You can similarly compute each conditional probability to find the the remaining conditional expectations.



-3x + 3y = 12<u /> ⇒ -12x + 4y = 48
4x + 2y = 20 ⇒ <u>12x + 6y = 60</u>
<u>-2y</u> = <u>-12</u>
-2 -2
y = 6
4x + 2(6) = 20
4x + 12 = 20
<u> -12 -12</u>
<u> 4x</u> =<u> 8</u>
4 4
x = 2
(x, y) = (2, 6)
Answer: 
Step-by-step explanation:
Given :
5 ≤ 4x− 1 < 7
the equation could be spitted into 2
1. 
ii. 
solving them separately , we have

divide through by 4

solving (ii) we have

add 1 to both sides



combining the solutions , we have 
Answer:
6
Step-by-step explanation: