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maks197457 [2]
2 years ago
7

In a study of helicopter usage and patient survival, among the 56,074 patients transported by helicopter, 235 of them

SAT
1 answer:
xxMikexx [17]2 years ago
6 0

Using the hypergeometric distribution, it is found that the probability is 0.845 = 84.5%.

--------------------

  • The patients are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

Combination formula:

is the number of different combinations of x objects from a set of n elements, given as:

C_{n,x} = \frac{n!}{x!(n-x)!}

--------------------

  • 56074 patients, thus N = 56074
  • Sample of 40, thus, n = 40
  • 235 left against medical advice, thus, k = 235.

The probability that none left against medical advice is P(X = 0), so:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,56074,40,235) = \frac{C_{235,0}*C_{55839,40}}{C_{56074,40}} = 0.845

The probability is 0.845 = 84.5%.

A similar problem is given at brainly.com/question/24008577

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