<span>10!/5! =10*9*8*7*6=30,240;;
If order is not considered, 10C5 =10!/5!5!=252 </span>
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
<u>ANSWER TO PART A</u>
The given triangle has vertices 
The mapping for rotation through 
counterclockwise has the mapping
Therefore
We plot all this point and connect them with straight lines.
ANSWER TO PART B
For a reflection across the y-axis we negate the x coordinates.
The mapping is
Therefore
We plot all this point and connect them with straight lines.
See graph in attachment
Answer:
16 1/12
Step-by-step explanation:
The LCD of 6 1/3 + 5 1/2 + 4 1/4 is 12; 12 is evenly divisible by 3, 2 and 4.
We can rewrite this expression as:
6 + 5 + 4 + 1/3 + 1/2 + 1/4, or
15 +4/12 + 6/12 + 3/12, or
15 + 13/12, or
16 1/12
