The usual approach to these is to square the radicals until they are gone.
Each time the equation is squared, the possibility of an extraneous root is introduced. Here, x=3 is extraneous: it does not satisfy the original equation.
The solution is x = -1.
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Using a graphing calculator to solve the original equation can avoid extraneous solutions. The attachment shows only the solution x = -1. Rather than use f(x) = 2, we have rewritten the equation to f(x)-2 = 0. The graphing calculator is really good at showing the function values at the x-intercepts.
6.34x 10-1 because you take the decimal and put it in between the 6 and the 3 and then you figure out how many times destiny needs to move and if it needs moved to the left it is a negative and since it only does once it’s just -1