Answer:
Step-by-step explanation:
Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.
To find : A 99% confidence interval for the mean yield when the new catalyst is used ?
Solution :
Let X be the yield of the batches.
We have given, n=10 ,
, s=5.8%
Since the size of the sample is small.
We will use the student's t statistic to construct a 995 confidence interval.

From the t-table with 9 degree of freedom for 


The 99% confidence interval is given by,




Answer:
$144.70
Step-by-step explanation:
Calculation to determine how much greater will the amount of interest capitalized be than the minimum amount that she could pay to prevent interest capitalization
First step is to determine the Interest only monthly repayments
Using this formula
I=Prt
where,
P=$6925
r=0.05/1
t=1
Let plug in the formula
I=6925*0.05/12
I= $28.854166666
Second step is to determine the amount she will owe after 4 years
Using this formula
S=P(1+r)n
Let plug in the formula
S=6925*(1+0.05/12)4*12
S=6925*(1+0.05/12)48
S=$8454.70
Third step is to determine the Interest part
Interest =8454.70 - 6925
Interest = $1529.70
Now let determine the how much greater will the amount of interest capitalized be
Interest capitalized=1529.70 - 1385.00
Interest capitalized =$144.70
Therefore how much greater will the amount of interest capitalized be than the minimum amount that she could pay to prevent interest capitalization is $144.70
3/4's obviously because the percentage is bigger.
Answer:
90 arrangements
Step-by-step explanation:
Since there are no repititions of letters, there are unique 10 letters in total.
THe number of arrangements would be 2 permutation 10. We need the formula for permutation. That is:

Now, n = 10 [total] and r is 2, so we have:

So, there can be 90 arrangements
Answer:
At these rates Sydney read 10 pages per hour more than Zander.
Step-by-step explanation:
Zander read
pages in
of an hour.
Therefore, pages read by Zander in 1 hour = 
= 
= 
= 55 pages per hour
Sydney read
pages in
of an hours.
Pages read by Sydney in 1 hour = 
= 
= 65 pages per hour
Therefore, number of pages read more by Sydney as compared to Zander,
= 65 - 55
= 10 pages per hour
At these rates Sydney read 10 pages per hour more than Zander.