Answer: Choice A) 4/5
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Work Shown:
cos^2(theta) + sin^2(theta) = 1
(-3/5)^2 + sin^2(theta) = 1
9/25 + sin^2(theta) = 1
9/25 + sin^2(theta) - 9/25 = 1 - 9/25
sin^2(theta) = 1 - 9/25
sin^2(theta) = 25/25 - 9/25
sin^2(theta) = (25 - 9)/25
sin^2(theta) = 16/25
sqrt[sin^2(theta)] = sqrt[16/25]
sin(theta) = 4/5
The fact that sine is positive in quadrant 2 means that the result is positive.
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There is no one ordered pair that makes the equation true, this is a line which has infinitely many ordered pairs that are true...
2x+y=11 subtract 2x from both sides and you have the line in slope intercept form..
y=11-2x
For any real given value of x, you will get one real unique corresponding value for y, resulting in infinitely many unique (x,y) values, points, or ordered pairs, satisfying the given equation.
I assume that you were given "choices" to pick from because of the above reality. So if any of your choices does not satisfy y=11-2x it is not an ordered pair satisfying the equation.
Answer:
Gradient of A: 2
Gradient of B: -1
Step-by-step explanation:
Gradient = change in y/change in x
✔️Gradient of A using two points on line A, (2, 5) and (0, 1):
Gradient = (1 - 5)/(0 - 2) = -4/-2
Simplify
Gradient of A = 2
✔️Gradient of B using two points on line B, (0, 5) and (5, 0):
Gradient = (0 - 5)/(5 - 0) = -5/5
Simplify
Gradient of B = -1
Answer:
the numerator is 31 and the bottom is 8
Step-by-step explanation:
