Question

PLEASE HELP ME!!

Answer 1

The first three standard deviation for coSport include;

• 1 standard deviation above and below the mean = 6.9 and 6.1
• 2 standard deviation above and below the mean = 7.3 and 5.7
• 3 standard deviation above and below the mean = 7.7 and 5.3

The first three standard deviation for Blockbuster include;

• 1 standard deviation above and below the mean = 5.2 and 4.0
• 2 standard deviation above and below the mean = 5.8 and 3.4
• 3 standard deviation above and below the mean = 6.4 and 2.8

"Check the image I added for the plot of the normal distribution"

In the given chart;

sample size of the coSport, = 400

the mean of the coSport, M = 6.5

standard deviation of the coSport, d = 0.4

The first standard deviation above and below the mean for coSport is calculated as;

at 34% of the sample size = 0.34 x 400 = 136

above the mean = M + d = 6.5 + 0.4 = 6.9

below the mean = M - d = 6.5 - 0.4 = 6.1

The second standard deviation above and below the mean for coSport is calculated as;

at 14% of the sample size = 0.14 x 400 = 56

above the mean = M + 2d = 6.5 + 2(0.4) = 7.3

below the mean = M - 2d = 6.5 - 2(0.4) = 5.7

The third standard deviation above and below the mean for coSport is calculated as;

at 2% of the sample size = 0.02 x 400 = 8

above the mean = M + 3d = 6.5 + 3(0.4) = 7.7

below the mean = M - 3d = 6.5 - 3(0.4) = 5.3

Also In the given chart;

• sample size of the Blockbuster, = 600

• the mean of the Blockbuster, M = 4.6

• standard deviation of the Blockbuster, d = 0.6

The first standard deviation above and below the mean for Blockbuster is calculated as;

at 34% of the sample size = 0.34 x 600 = 204

above the mean = M + d = 4.6 + 0.6 = 5.2

below the mean = M - d = 4.6 - 0.6 = 4

The second standard deviation above and below the mean for Blockbuster is calculated as;

at 14% of the sample size = 0.14 x 600 = 84

above the mean = M + 2d = 4.6 + 2(0.6) = 5.8

below the mean = M - 2d = 4.6 - 2(0.6) = 3.4

The third standard deviation above and below the mean for Blockbuster is calculated as;

at 2% of the sample size = 0.02 x 600 = 12

above the mean = M + 3d = 4.6 + 3(0.6) = 6.4

below the mean = M - 3d = 4.6 - 2(0.6) = 2.8

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