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oee [108]
3 years ago
13

Find the greatest number that divides 36,45 and 63 without leaving a remainder​

Mathematics
2 answers:
Tcecarenko [31]3 years ago
6 0
Using the prime factorization method
36= 2x2x3x3
45 = 5x3x3
63= 3x3x7
Therefore the greatest number common to both is 3x3 = 9
bazaltina [42]3 years ago
4 0
<h2>Answer:  9</h2>

Step-by-step explanation:

I like to write out a multiplication of the lowest factors for each of the numbers and then compare them to find what might be the Greatest Common Factor.

Now,

36 = 2 × 2 × <u>3 × 3</u>

45 = <u>3 × 3</u> × 5

63 = <u>3 × 3</u> × 7

∴ the GCF is 9.

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7.053 x 10^6 in standard form
likoan [24]

Answer:

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Step-by-step explanation:

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4 years ago
In how many ways can a set of two nonnegative integers less than 100 be chosen?
hichkok12 [17]

Answer: 4950

Step-by-step explanation:

The number of possible combinations of n things taken r at a time is given by :-

C(n,r)=\dfrac{n!}{r!(n-r)!}

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So, the number of combinations of choosing 2 out of them = C(100,2)=\dfrac{100!}{2!98!}=\dfrac{100\times99\times98!}{2\times98!}\\\\=\dfrac{100\times99}{2}\\\\=50\times 99\\\\=4950

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5 0
3 years ago
Solve for x: x – 23 = 2
geniusboy [140]

Answer:

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Step-by-step explanation:

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Selan will use dot plots to compare the number of siblings of her classmates. If she plots the girls siblings in one plot and th
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