3 years ago

Find the greatest number that divides 36,45 and 63 without leaving a remainder

2 answers:

6 0

Using the prime factorization method
36= 2x2x3x3
45 = 5x3x3
63= 3x3x7
Therefore the greatest number common to both is 3x3 = 9

bazaltina [42]3 years ago

4 0

<h2>Answer: 9</h2>

Step-by-step explanation:

I like to write out a multiplication of the lowest factors for each of the numbers and then compare them to find what might be the Greatest Common Factor.

Now,

36 = 2 × 2 × <u>3 × 3</u>

45 = <u>3 × 3</u> × 5

63 = <u>3 × 3</u> × 7

∴ the GCF is 9.

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Find the greatest number that divides 36,45 and 63 without leaving a remainder​

Find the greatest number that divides 36,45 and 63 without leaving a remainder