Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
Answer: y=-2x+6
Step-by-step explanation:

So
. We can substitute (0, 6) to get:
6 = 2(0)+b
b=6.
Meaning y=-2x+6.
Answer:
For this transition of equations, the graph of g(x) will be translated left 2 units with respect to the graph of f(x), so your answer choice will be A.
Step-by-step explanation:
In this equation, g(x) is changed by adding 2 and closing part of the equation in parenthases, this results in the translation 2 units left, which can be proven by a graph and my answer.
Answer:
C.?
Step-by-step explanation:
wheres the pic??