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denpristay [2]
3 years ago
15

I need help on all three of these questions

Mathematics
1 answer:
Ksju [112]3 years ago
3 0
A 20.o don’t mind this hhfhdjdjjdndnfndnfhfhfhfhhfhfhfjfj
You might be interested in
Write a quadratic function in vertex form for the function whose graph has it's vertex at (5,4) and passes through the point (7,
Ivenika [448]

y = - \frac{3}{4} (x - 5)² + 4

the equation of a quadratic in standard form is

y = a(x - h)² + k ( where (h , k ) are the coordinates of the vertex and a is a multiplier )

given vertex = ( 5, 4 ) then

y = a(x - 5)² + 4 ( to find a substitute (7 , 1 ) into the equation )

1= 4a + 4

4a = - 3 ⇒ a = - \frac{3}{4}

y = - \frac{3}{4} (x - 5)² + 4 ← ( in vertex form )


8 0
3 years ago
HELP Please THANKS:((((
guapka [62]
Answer is C.

w + c <= 27

hope it helps
7 0
3 years ago
Read 2 more answers
A string of decorative lights is 28 feet long. The first light on the string is 16 inches from the plug. If the lights on the st
lubasha [3.4K]
There are 80 lights. 28 x 12 divided by 4 minus 4 lights for the 16 inches before the first light.
6 0
3 years ago
8 sin2 x + cos x - 5 = 0
soldier1979 [14.2K]

8 {sin}^{2} x + cos \: x - 5 = 0

recall \: that \:  {sin}^{2} x +  {cos}^{2} x = 1

then \:  {sin}^{2} x = 1 -  {cos}^{2} x

then substitute,

8( 1 - {cos}^{2} x)  + cos \: x - 5 = 0

After Further Simplication,

8 {cos}^{2} x - cos \: x - 3 = 0

let \: y =  \cos(x)

8 {y}^{2}  - y - 3 = 0

use quadratic formulae

y = 0.375 \: or \:  - 0.25

therefore

\cos(x)  = 0.375 \: or \:  - 0.25

x = 70degrees \: or \: 104.5degrees

4 0
3 years ago
4b-4=3 b+3 What’s b=
julia-pushkina [17]

Answer:

b = 7

Step-by-step explanation:

4b - 4 = 3b + 3

4b - 3b = 3 + 4

b = 7

7 0
3 years ago
Read 2 more answers
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